10th-Grade-Math---USA

System-of-Linear-Equations-and-Inequalities

Easy

Question

The solution of system of equations 5x + 10y = 20 and – 6x – 5y = - 3 is

(2, 3)
(-2, 3)
(2, 4)
(2, -4)

The correct answer is: (-2, 3)

The point that is not a solution of the system of inequalities is
y ≥ - 2x + 1 ; y > x + 2

10th-Grade-Math---USASystem-of-Linear-Equations-and-Inequalities

System-of-Linear-Equations-and-Inequalities

10th-Grade-Math---USA

Number of solutions for the system of inequations y ≥ – x + 2 ; y < – x – 2

10th-Grade-Math---USASystem-of-Linear-Equations-and-Inequalities

System-of-Linear-Equations-and-Inequalities

10th-Grade-Math---USA

The point that is a solution of the system of linear inequations is
y > x – 2 ; y < – x + 1

10th-Grade-Math---USASystem-of-Linear-Equations-and-Inequalities

System-of-Linear-Equations-and-Inequalities

10th-Grade-Math---USA

Number of solutions to the system of equations $y equals 1 half x plus 4 text and end text y equals 1 half x plus 1$ is

10th-Grade-Math---USASystem-of-Linear-Equations-and-Inequalities

System-of-Linear-Equations-and-Inequalities

10th-Grade-Math---USA

The solution of system of equations y = 2x + 2 and y = -x -4 is

10th-Grade-Math---USASystem-of-Linear-Equations-and-Inequalities

System-of-Linear-Equations-and-Inequalities

10th-Grade-Math---USA

The solution of system of equations 2x + 3y = -6 and 2x + y = 2 is

10th-Grade-Math---USASystem-of-Linear-Equations-and-Inequalities

Polynomial-and-Rational-Expressions

10th-Grade-Math---USA

$fraction numerator 5 a over denominator a plus 3 end fraction cross times fraction numerator a squared plus a minus 6 over denominator a squared plus 2 a plus 1 end fraction cross times left parenthesis a plus 1 right parenthesis$ =

10th-Grade-Math---USAPolynomial-and-Rational-Expressions

Polynomial-and-Rational-Expressions

10th-Grade-Math---USA

The quotient of rational functions $fraction numerator x squared minus 1 over denominator x squared minus 4 x plus 3 end fraction divided by fraction numerator x plus 1 over denominator x minus 3 end fraction$ is

10th-Grade-Math---USAPolynomial-and-Rational-Expressions

Polynomial-and-Rational-Expressions

10th-Grade-Math---USA

$1 plus fraction numerator 5 over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 1 right parenthesis end fraction$ =

10th-Grade-Math---USAPolynomial-and-Rational-Expressions

Polynomial-and-Rational-Expressions

10th-Grade-Math---USA

$1 half plus fraction numerator 1 over denominator 1 half plus fraction numerator 1 over denominator 1 half end fraction end fraction$ =

10th-Grade-Math---USAPolynomial-and-Rational-Expressions

Polynomial-and-Rational-Expressions

10th-Grade-Math---USA

Solve for $x colon fraction numerator 1 over denominator 2 left parenthesis x plus 3 right parenthesis end fraction equals 5 over 4$

10th-Grade-Math---USAPolynomial-and-Rational-Expressions

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The solution of system of equations 5x + 10y = 20 and – 6x – 5y = - 3 is

(2, 3)(-2, 3)(2, 4)(2, -4)

The correct answer is: (-2, 3)

Related Questions to study

The point that is not a solution of the system of inequalities is y ≥ - 2x + 1 ; y > x + 2

The point that is not a solution of the system of inequalities is y ≥ - 2x + 1 ; y > x + 2

Number of solutions for the system of inequations y ≥ – x + 2 ; y < – x – 2

Number of solutions for the system of inequations y ≥ – x + 2 ; y < – x – 2

The point that is a solution of the system of linear inequations isy > x – 2 ; y < – x + 1

The point that is a solution of the system of linear inequations isy > x – 2 ; y < – x + 1

Solve the system of equations 3x – 4y = 8 and 5x + 4y = -24

Solve the system of equations 3x – 4y = 8 and 5x + 4y = -24

Identify the solution of system of equation, from the graph.

Identify the solution of system of equation, from the graph.

Solve the system of equations 2x – 3y = 7 and y = 3x - 7

Solve the system of equations 2x – 3y = 7 and y = 3x - 7

From the graph, identify the solution of the system of equations

From the graph, identify the solution of the system of equations

Number of solutions to the system of equations is

Number of solutions to the system of equations is

The solution of system of equations y = 2x + 2 and y = -x -4 is

The solution of system of equations y = 2x + 2 and y = -x -4 is

The solution of system of equations 2x + 3y = -6 and 2x + y = 2 is

The solution of system of equations 2x + 3y = -6 and 2x + y = 2 is

=

=

The quotient of rational functions is

The quotient of rational functions is

=

=

=

=

Solve for

Solve for

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(2, 3)
(-2, 3)
(2, 4)
(2, -4)

The point that is not a solution of the system of inequalities is
y ≥ - 2x + 1 ; y > x + 2

The point that is not a solution of the system of inequalities is
y ≥ - 2x + 1 ; y > x + 2

The point that is a solution of the system of linear inequations is
y > x – 2 ; y < – x + 1

The point that is a solution of the system of linear inequations is
y > x – 2 ; y < – x + 1

Number of solutions to the system of equations $y equals 1 half x plus 4 text and end text y equals 1 half x plus 1$ is

Number of solutions to the system of equations $y equals 1 half x plus 4 text and end text y equals 1 half x plus 1$ is

$fraction numerator 5 a over denominator a plus 3 end fraction cross times fraction numerator a squared plus a minus 6 over denominator a squared plus 2 a plus 1 end fraction cross times left parenthesis a plus 1 right parenthesis$ =

$fraction numerator 5 a over denominator a plus 3 end fraction cross times fraction numerator a squared plus a minus 6 over denominator a squared plus 2 a plus 1 end fraction cross times left parenthesis a plus 1 right parenthesis$ =

The quotient of rational functions $fraction numerator x squared minus 1 over denominator x squared minus 4 x plus 3 end fraction divided by fraction numerator x plus 1 over denominator x minus 3 end fraction$ is

The quotient of rational functions $fraction numerator x squared minus 1 over denominator x squared minus 4 x plus 3 end fraction divided by fraction numerator x plus 1 over denominator x minus 3 end fraction$ is

$1 plus fraction numerator 5 over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 1 right parenthesis end fraction$ =

$1 plus fraction numerator 5 over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 1 right parenthesis end fraction$ =

$1 half plus fraction numerator 1 over denominator 1 half plus fraction numerator 1 over denominator 1 half end fraction end fraction$ =

$1 half plus fraction numerator 1 over denominator 1 half plus fraction numerator 1 over denominator 1 half end fraction end fraction$ =

Solve for $x colon fraction numerator 1 over denominator 2 left parenthesis x plus 3 right parenthesis end fraction equals 5 over 4$

Solve for $x colon fraction numerator 1 over denominator 2 left parenthesis x plus 3 right parenthesis end fraction equals 5 over 4$