Solution for the question - if (5)/(2)x^(o+),(7)/(2)x^(o+),60^(o+) are the interior angles of deltaabc, then the largest angle of delta abc is 80o

9th-Grade-Math---USA

Congruent-Triangles

Easy

Question

$text If end text 5 over 2 straight x to the power of straight o comma 7 over 2 straight x to the power of straight o comma 60 to the power of straight o$ are the interior angles of $capital delta$ ABC, then the largest angle of $capital delta$ ABC is

50^o
60^o
70^o
80^o

The correct answer is: 70^o

In
$straight m angle straight A space equals$

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of y is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

If $angle A & angle B$ are supplementary, $space m angle A equals left parenthesis 4 x plus 6 right parenthesis degree comma m angle B equals left parenthesis 7 x minus 24 right parenthesis degree$ , then $m angle A$ is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

Suppose $capital delta A B C approximately equal to capital delta E F D comma capital delta E F D approximately equal to capital delta G I H comma m angle A equals 90 degree & m angle F equals 20 degree$ , then $m angle H$ =

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

Classify the triangle $capital delta text DEF end text$ if $space m angle D equals left parenthesis 4 x plus 2 right parenthesis degree semicolon m angle E equals left parenthesis 6 x minus 30 right parenthesis degree & m angle F equals 3 x degree$ is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

$text If in end text capital delta A B C m angle A equals x degree semicolon m angle B equals left parenthesis 5 x right parenthesis degree semicolon m angle C equals left parenthesis x plus 19 right parenthesis degree text , end text$ then the value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

$text If end text increment A B C approximately equal to capital delta D E F semicolon m angle A equals 70 degree comma m angle B equals 60 degree comma m angle C equals 50 degree comma m angle D equals left parenthesis 3 x plus 10 right parenthesis degree$ , then the value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The postulate we use to prove $increment A B C approximately equal to capital delta H J K$ is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of x is

9th-Grade-Math---USACongruent-Triangles

Congruent-Triangles

9th-Grade-Math---USA

The value of x is

9th-Grade-Math---USACongruent-Triangles

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are the interior angles of ABC, then the largest angle of ABC is

50o60o70o80o

The correct answer is: 70o

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$text If end text 5 over 2 straight x to the power of straight o comma 7 over 2 straight x to the power of straight o comma 60 to the power of straight o$ are the interior angles of $capital delta$ ABC, then the largest angle of $capital delta$ ABC is

50^o
60^o
70^o
80^o

The correct answer is: 70^o

In
$straight m angle straight A space equals$

In
$straight m angle straight A space equals$

If $angle A & angle B$ are supplementary, $space m angle A equals left parenthesis 4 x plus 6 right parenthesis degree comma m angle B equals left parenthesis 7 x minus 24 right parenthesis degree$ , then $m angle A$ is

If $angle A & angle B$ are supplementary, $space m angle A equals left parenthesis 4 x plus 6 right parenthesis degree comma m angle B equals left parenthesis 7 x minus 24 right parenthesis degree$ , then $m angle A$ is

Suppose $capital delta A B C approximately equal to capital delta E F D comma capital delta E F D approximately equal to capital delta G I H comma m angle A equals 90 degree & m angle F equals 20 degree$ , then $m angle H$ =

Suppose $capital delta A B C approximately equal to capital delta E F D comma capital delta E F D approximately equal to capital delta G I H comma m angle A equals 90 degree & m angle F equals 20 degree$ , then $m angle H$ =

Classify the triangle $capital delta text DEF end text$ if $space m angle D equals left parenthesis 4 x plus 2 right parenthesis degree semicolon m angle E equals left parenthesis 6 x minus 30 right parenthesis degree & m angle F equals 3 x degree$ is

Classify the triangle $capital delta text DEF end text$ if $space m angle D equals left parenthesis 4 x plus 2 right parenthesis degree semicolon m angle E equals left parenthesis 6 x minus 30 right parenthesis degree & m angle F equals 3 x degree$ is

$text If in end text capital delta A B C m angle A equals x degree semicolon m angle B equals left parenthesis 5 x right parenthesis degree semicolon m angle C equals left parenthesis x plus 19 right parenthesis degree text , end text$ then the value of x is

$text If in end text capital delta A B C m angle A equals x degree semicolon m angle B equals left parenthesis 5 x right parenthesis degree semicolon m angle C equals left parenthesis x plus 19 right parenthesis degree text , end text$ then the value of x is

$text If end text increment A B C approximately equal to capital delta D E F semicolon m angle A equals 70 degree comma m angle B equals 60 degree comma m angle C equals 50 degree comma m angle D equals left parenthesis 3 x plus 10 right parenthesis degree$ , then the value of x is

$text If end text increment A B C approximately equal to capital delta D E F semicolon m angle A equals 70 degree comma m angle B equals 60 degree comma m angle C equals 50 degree comma m angle D equals left parenthesis 3 x plus 10 right parenthesis degree$ , then the value of x is

The postulate we use to prove $increment A B C approximately equal to capital delta H J K$ is

The postulate we use to prove $increment A B C approximately equal to capital delta H J K$ is