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Chemistry-

General

Easy

Question

A reaction is, $A plus B rightwards arrow C plus D$ . Initially we start with equal concentrations of $A$ and $B$ . At equilibrium, we find the moles of $C$ are two times of $A$ . What is the equilibrium constant of the reaction?

2
4
$\frac{1}{2}$
$\frac{1}{4}$

The correct answer is: 4

$A plus B rightwards harpoon over leftwards harpoon C plus D$
$a blank a blank 2 a blank 2 a$ at equilibrium
$therefore blank K subscript c end subscript equals fraction numerator open square brackets C close square brackets left square bracket D right square bracket over denominator open square brackets A close square brackets left square bracket B right square bracket end fraction$
$equals fraction numerator 2 a cross times 2 a over denominator a cross times a end fraction equals 4$

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