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Question

A student wants to prepare a saturated solution of A g to the power of plus end exponent ion. He has got three samples A g C l open parentheses K subscript s p end subscript equals 10 to the power of negative 10 end exponent close parentheses comma blank A g B r left parenthesis K subscript s p end subscript equals 10 to the power of negative 13 end exponent right parenthesis and A g subscript 2 end subscript C r O subscript 4 end subscript open parentheses K subscript s p end subscript equals 10 to the power of negative 12 end exponent close parentheses. Which of the above compound will be used by him using minimum weight to prepare the saturated solution?

  1. A g C l  
  2. A g B r  
  3. A g subscript 2 end subscript C r O subscript 4 end subscript  
  4. All of these  

The correct answer is: A g B r


    (s) or mole of A g C l needed equals square root of K subscript s p end subscript end root equals 10 to the power of negative 5 end exponent
    (s) or mole of A g B r needed equals square root of K subscript s p end subscript end root equals 3.16 cross times 10 to the power of negative 7 end exponent
    (s) or mole of A g subscript 2 end subscript C r O subscript 4 end subscript needed equals root index 3 of fraction numerator K subscript s p end subscript over denominator 4 end fraction end root equals 0.62 cross times 10 to the power of negative 4 end exponent
    therefore Weight of A g C l equals 10 to the power of negative 5 end exponent cross times 143.5 equals 1.435 cross times 10 to the power of negative 3 end exponent g
    therefore Weight of A g B r equals 3.16 cross times 10 to the power of negative 7 end exponent cross times 188 equals 5.94 cross times 10 to the power of negative 5 end exponent g
    therefore Weight of A g subscript 2 end subscript C r O subscript 4 end subscript equals 6.2 cross times 10 to the power of negative 5 end exponent cross times 332 equals 2.058 cross times 10 to the power of negative 2 end exponent g

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