Chemistry-
General
Easy

Question

How many gram of N a O H must be present in one l i t r e of the solution to give it a p H equals 12 ?

  1. 0.20 blank g blank l i t r e to the power of negative 1 end exponent  
  2. 0.4 blank g blank l i t r e to the power of negative 1 end exponent  
  3. 4.0 blank g blank l i t r e to the power of negative 1 end exponent  
  4. 0.10 blank g blank l i t r e to the power of negative 1 end exponent  

The correct answer is: 0.4 blank g blank l i t r e to the power of negative 1 end exponent


    open square brackets H to the power of plus end exponent close square brackets equals 10 to the power of negative 12 end exponent
    open square brackets O H to the power of minus end exponent close square brackets equals 10 to the power of negative 2 end exponent
    fraction numerator blank w over denominator 40 end fraction equals 10 to the power of negative 2 end exponent
    o r blank w equals 0.4 blank g blank l i t r e to the power of negative 1 end exponent

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