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Chemistry-

General

Easy

Question

Of the following which change will shift the reaction towards the product? $I subscript 2 end subscript open parentheses g close parentheses rightwards harpoon over leftwards harpoon 2 I open parentheses g close parentheses comma blank increment H degree subscript r end subscript open parentheses 298 blank K close parentheses equals plus 150 blank k J$

Increase in temperature
Increase in total pressure
Increase in concentration of I
Decrease in concentration of $I_{2}$

The correct answer is: Increase in temperature

$increment H$ is positive, so it will shift toward the product by increasing temperature

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$K subscript a end subscript$ forHCN is $5 cross times 10 to the power of negative 10 end exponent$ at $25 ℃$ . For maintaining a constant $p H equals 9$ , the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution is

$K subscript a end subscript$ forHCN is $5 cross times 10 to the power of negative 10 end exponent$ at $25 ℃$ . For maintaining a constant $p H equals 9$ , the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution is

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Which favours the backward reaction in a chemical equilibrium?

Which favours the backward reaction in a chemical equilibrium?

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The $left square bracket H to the power of plus end exponent right square bracket$ ion concentration in $0.001 blank M$ acetic acid is $1.34 cross times 10 to the power of negative 4 end exponent g blank i o n divided by l i t r e.$ The $open square brackets H to the power of plus end exponent close square brackets$ ion concentration of $0.164 g blank o f blank C H subscript 3 end subscript C O O N a$ is added to a $l i t r e$ of $0.001 blank M C H subscript 3 end subscript C O O H$ will be:

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The equilibrium constant $K subscript c end subscript$ for $A open parentheses g close parentheses rightwards harpoon over leftwards harpoon B open parentheses g close parentheses$ is 1.1, Gas $B$ will have molar concentration greater than 1 if :

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The solubility product of $B a S O subscript 4 end subscript$ is $1.5 cross times 10 to the power of negative 9 end exponent$ . The precipitation in a 0.01 M $B a to the power of 2 plus end exponent$ solution will start, on adding $H subscript 2 end subscript S O subscript 4 end subscript$ of concentration

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parallel

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