Chemistry-
General
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Question

Product on monobromination of this compound is

  1.    
  2.    
  3.    
  4.    

The correct answer is:



    It is electrophilic substitution, so electrophile must be attacked on o/p-position due to higher electron density on this position. In this ring, the attached –NH- group will have high electron density due to resonance and o r t h o position is blocked, so electrophile is attached on p a r a position.

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