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General
Chemistry-

Chemistry-General
General
Chemistry-

The ionization constant of in water is 5.6 ×´ 10-10 at 25oC. The rate constant for the reaction of and OH- to form NH3 and H2O at 25oC is 3.4 × 1010 L mol-1 s-1. The rate constant for proton transfer from water to NH3 is

The ionization constant of in water is 5.6 ×´ 10-10 at 25oC. The rate constant for the reaction of and OH- to form NH3 and H2O at 25oC is 3.4 × 1010 L mol-1 s-1. The rate constant for proton transfer from water to NH3 is

Chemistry-General
General
Maths-

For the curve y2 = (x + a)3 the square of the sub tangent varies as

For such questions, we should know the concept of subnormal and subtangent.

For the curve y2 = (x + a)3 the square of the sub tangent varies as

Maths-General

For such questions, we should know the concept of subnormal and subtangent.

parallel
General
Maths-

The length of the subtangent at any point on y = f(x) is 3/8 and the length of the subnormal is 24 then the ordinate of the point is

For such questions, we should know the formula to find subtangent and subnormal.

The length of the subtangent at any point on y = f(x) is 3/8 and the length of the subnormal is 24 then the ordinate of the point is

Maths-General

For such questions, we should know the formula to find subtangent and subnormal.

General
Maths-

The length of the portion of the tangent at any point on the curve x2/3 + y2/3 = a2/3 intercepted between the axis is

The length of the portion of the tangent at any point on the curve x2/3 + y2/3 = a2/3 intercepted between the axis is

Maths-General
General
Maths-

The equation of the tangent to the curve x2 + 2y = 8 which is the perpendicular to x – 2y + 1 = 0 is

For such questions, we should know the formula to find the tangent and slope of lines and curves.

The equation of the tangent to the curve x2 + 2y = 8 which is the perpendicular to x – 2y + 1 = 0 is

Maths-General

For such questions, we should know the formula to find the tangent and slope of lines and curves.

parallel
General
Maths-

In an isosceles triangle the ends of the base are (2a, 0) and (0, a) and one side is parallel to x – axis. The third vertex is

In an isosceles triangle the ends of the base are (2a, 0) and (0, a) and one side is parallel to x – axis. The third vertex is

Maths-General
General
Maths-

If x + 2y + 3 = 0, x + 2y – 7 = 0 and 2x – y – 4 = 0 form the sides of square, the equation of the fourth side is

For such questions, we should know properties of square. We should know the formula to find distance between two parallel lines.

If x + 2y + 3 = 0, x + 2y – 7 = 0 and 2x – y – 4 = 0 form the sides of square, the equation of the fourth side is

Maths-General

For such questions, we should know properties of square. We should know the formula to find distance between two parallel lines.

General
Maths-

The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is

For such questions, we should know properties of concurrent lines.

The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is

Maths-General

For such questions, we should know properties of concurrent lines.

parallel
General
Maths-

The distance of the line 2x – 3y = 4 from the point (1, 1) in the direction of the line x + y = 1 is

The distance of the line 2x – 3y = 4 from the point (1, 1) in the direction of the line x + y = 1 is

Maths-General
General
Maths-

The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12). The orthocentre of this triangle is

The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12). The orthocentre of this triangle is

Maths-General
General
Maths-

The image of the point A (1, 2) by the line mirror y = x is the point B and the image of B by line mirror y = 0 is the point

The image of the point A (1, 2) by the line mirror y = x is the point B and the image of B by line mirror y = 0 is the point

Maths-General
parallel
General
Maths-

If y equals T a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus a to the power of 2 end exponent x to the power of 2 end exponent end root minus 1 over denominator a x end fraction close parentheses text  then  end text open parentheses 1 plus a to the power of 2 end exponent x to the power of 2 end exponent close parentheses y to the power of parallel to end exponent plus 2 a to the power of 2 end exponent x y to the power of ´ end exponent equals

For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.

If y equals T a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus a to the power of 2 end exponent x to the power of 2 end exponent end root minus 1 over denominator a x end fraction close parentheses text  then  end text open parentheses 1 plus a to the power of 2 end exponent x to the power of 2 end exponent close parentheses y to the power of parallel to end exponent plus 2 a to the power of 2 end exponent x y to the power of ´ end exponent equals

Maths-General

For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.

General
Maths-

If y equals c o s to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a to the power of 2 end exponent minus x to the power of 2 end exponent over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses plus s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 2 a x over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses text  then  end text fraction numerator d y over denominator d x end fraction equals

For such questions, we should know the formulas of inverse functions.

If y equals c o s to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a to the power of 2 end exponent minus x to the power of 2 end exponent over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses plus s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 2 a x over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses text  then  end text fraction numerator d y over denominator d x end fraction equals

Maths-General

For such questions, we should know the formulas of inverse functions.

General
Maths-

If y equals s i n invisible function application 2 x s i n invisible function application 3 x s i n invisible function application 4 x text  then  end text y to the power of parallel to end exponent equals

For such questions, we should know different formulas.

If y equals s i n invisible function application 2 x s i n invisible function application 3 x s i n invisible function application 4 x text  then  end text y to the power of parallel to end exponent equals

Maths-General

For such questions, we should know different formulas.

parallel

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