Chemistry-
General
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Question

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

S subscript N to the power of 1 end exponent end subscript reaction is:

  1. single step reaction    
  2. two step reaction    
  3. a reaction involving free radical intermediate    
  4. a reaction involving carbocation intermediate    

The correct answer is: a reaction involving carbocation intermediate

Related Questions to study

General
Chemistry-

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

In the graph 3 for S subscript N to the power of 1 end exponent end subscript reaction, the rate limiting step is the spontaneous dissociation of alkyl halide and is given by:

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

In the graph 3 for S subscript N to the power of 1 end exponent end subscript reaction, the rate limiting step is the spontaneous dissociation of alkyl halide and is given by:

Chemistry-General
General
Chemistry-

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

Select the correct statement(s) about the graph 2:

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

Select the correct statement(s) about the graph 2:

Chemistry-General
General
Chemistry-

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

In S subscript N to the power of 1 end exponent end subscript reaction, the hybridization changes in rate determination step. Select the correct change among the following:

SN1 reaction is a first order nucleophilic substitution, e.g.,

The concentration of nucleophile does not appear in the rate law expression:
Reaction rate = k[ RX]
In a multistep organic reaction, the rate-limiting step is the slowest step. Rate determining step is represented by the following energy level diagram:


A reaction energy level diagram for an S subscript N to the power of 1 end exponent end subscript reaction. The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate

In S subscript N to the power of 1 end exponent end subscript reaction, the hybridization changes in rate determination step. Select the correct change among the following:

Chemistry-General
parallel
General
Chemistry-

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
Neopentyl bromide undergoes dehydrohalogenation to give alkene even though it has no beta-hydrogen. This is due to:

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
Neopentyl bromide undergoes dehydrohalogenation to give alkene even though it has no beta-hydrogen. This is due to:

Chemistry-General
General
Chemistry-

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Br-omopentane is heated with potassium ethoxide in ethanol. The major product obtained is:

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Br-omopentane is heated with potassium ethoxide in ethanol. The major product obtained is:

Chemistry-General
General
Chemistry-

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.

This reaction is an example of:

The removal of two atoms or groups, one generally hydrogen open parentheses H to the power of plus end exponent close parentheses and the other a leaving group open parentheses L to the power of minus end exponent close parentheses resulting in the formation of unsaturated compound is known as elimination reaction.

In E subscript 1 end subscript (elimination) reactions, the C minus L bond is broken heterolytic ally (in step 1) to form a carbocation (as in S subscript N to the power of 1 end exponent end subscript reaction) in which open parentheses L to the power of minus end exponent close) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta-carbon atom by a base (nucleophile) to form an alkene. E subscript 1 end subscript reaction is favoured in compounds in which the leaving group is at secondary open parentheses 2 to the power of ring operator end exponent close parentheses to the power of ´ end exponent or tertiary open parentheses 3 to the power of ring operator end exponent close parentheses position. In E subscript 2 end subscript text end text left parenthesis e l i m i n a t i o n right parenthesis text end text r e a c t i o n s comma text end text t w o text end text s i g m a text end text b o n d s text end text a r e text end text b r o k e n text end text a n d text end text a formed simultaneously. E subscript 2 end subscript reactions occur in one step through a transition state.

E subscript 2 end subscript reactions are most common in haloalkanes (particularly, 1 to the power of ring operator end exponent) and better the leaving group higher is the E subscript 1 end subscript reaction. In E subscript 2 end subscript reactions, both the leaving groups should be antiplanar.
E subscript 1 end subscript cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.

This reaction is an example of:

Chemistry-General
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General
Maths-

For any real x, the expression 2 open parentheses K minus x close parentheses open square brackets x plus square root of x to the power of 2 end exponent plus K to the power of 2 end exponent end root close square brackets cannot exceed

For any real x, the expression 2 open parentheses K minus x close parentheses open square brackets x plus square root of x to the power of 2 end exponent plus K to the power of 2 end exponent end root close square brackets cannot exceed

Maths-General
General
Maths-

The number of real roots of open parentheses sin invisible function application 2 to the power of x end exponent close parentheses open parentheses cos invisible function application 2 to the power of x end exponent close parentheses equals fraction numerator 1 over denominator 4 end fraction open parentheses 2 to the power of x end exponent plus 2 to the power of negative x end exponent close parentheses is

The number of real roots of open parentheses sin invisible function application 2 to the power of x end exponent close parentheses open parentheses cos invisible function application 2 to the power of x end exponent close parentheses equals fraction numerator 1 over denominator 4 end fraction open parentheses 2 to the power of x end exponent plus 2 to the power of negative x end exponent close parentheses is

Maths-General
General
Maths-

If z1, z2, z3 are complex numbers such that∣z1∣=∣ z2 ∣=∣ z3 ∣=open vertical bar fraction numerator 1 over denominator z subscript 1 end subscript end fraction plus fraction numerator 1 over denominator z subscript 2 end subscript end fraction plus fraction numerator 1 over denominator z subscript 3 end subscript end fraction close vertical bar equals 1, thus, ∣ z1 + z2 + z3 ∣ is

If z1, z2, z3 are complex numbers such that∣z1∣=∣ z2 ∣=∣ z3 ∣=open vertical bar fraction numerator 1 over denominator z subscript 1 end subscript end fraction plus fraction numerator 1 over denominator z subscript 2 end subscript end fraction plus fraction numerator 1 over denominator z subscript 3 end subscript end fraction close vertical bar equals 1, thus, ∣ z1 + z2 + z3 ∣ is

Maths-General
parallel
General
Maths-

If the roots of the equation z2 + az + b = 0 are purely imaginary, then

If the roots of the equation z2 + az + b = 0 are purely imaginary, then

Maths-General
General
Maths-

The cube roots of unity

The cube roots of unity

Maths-General
General
Maths-

If z satisfies ∣ z − 1∣ < ∣ z + 3 ∣, then omega = 2z + 3 − i satisfies :

If z satisfies ∣ z − 1∣ < ∣ z + 3 ∣, then omega = 2z + 3 − i satisfies :

Maths-General
parallel
General
Maths-

A(z1), B(z2) and C(z3) be the vertices of an equilateral triangle in the argand plane such that ∣z1∣ = ∣z2∣ = ∣z3∣. Then which of the following is false ?

A(z1), B(z2) and C(z3) be the vertices of an equilateral triangle in the argand plane such that ∣z1∣ = ∣z2∣ = ∣z3∣. Then which of the following is false ?

Maths-General
General
Maths-

If the system of equations x-ky-z=0,kx-y-z=0,x+y-z=0 has a non-zero solution then the possible values of k are

For such questions, we should remember the requirement for non zero solution. We have to be careful when finding the determinant.

If the system of equations x-ky-z=0,kx-y-z=0,x+y-z=0 has a non-zero solution then the possible values of k are

Maths-General

For such questions, we should remember the requirement for non zero solution. We have to be careful when finding the determinant.

General
Maths-

If A equals open square brackets table row cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent plus e to the power of negative i x end exponent close parentheses end cell cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent minus e to the power of negative i x end exponent close parentheses end cell row cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent minus e to the power of negative i x end exponent close parentheses end cell cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent plus e to the power of negative i x end exponent close parentheses end cell end table close square brackets then A to the power of negative 1 end exponent exists

Whenever we have to find the inverse of the matrix, we should check the determinant of the matrix. The determinant must be non zero for a inverse to exist.

If A equals open square brackets table row cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent plus e to the power of negative i x end exponent close parentheses end cell cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent minus e to the power of negative i x end exponent close parentheses end cell row cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent minus e to the power of negative i x end exponent close parentheses end cell cell fraction numerator 1 over denominator 2 end fraction open parentheses e to the power of i x end exponent plus e to the power of negative i x end exponent close parentheses end cell end table close square brackets then A to the power of negative 1 end exponent exists

Maths-General

Whenever we have to find the inverse of the matrix, we should check the determinant of the matrix. The determinant must be non zero for a inverse to exist.

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