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The molar solubility of M left parenthesis O H right parenthesis subscript 3 end subscript in 0.4 M M open parentheses N O subscript 3 end subscript close parentheses subscript 3 end subscript blanksolution interms of solubility product of

  1. open parentheses K subscript s p end subscript divided by 10.8 close parentheses to the power of 1 divided by 3 end exponent    
  2. open parentheses K subscript s p end subscript divided by 3.6 close parentheses to the power of 1 divided by 3 end exponent    
  3. open parentheses K subscript s p end subscript divided by 10.8 close parentheses to the power of 1 divided by 4 end exponent    
  4. open parentheses K subscript s p end subscript divided by 0.4 close parentheses to the power of 1 divided by 3 end exponent    

The correct answer is: open parentheses K subscript s p end subscript divided by 10.8 close parentheses to the power of 1 divided by 3 end exponent

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