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    Chemistry-
    General
    Easy

    Question

    The number of spherical nodes in4 s orbital is

    1. 4    
    2. infinity    
    3. 2    
    4. 3    

    The correct answer is: 3

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    An orbital with l equals 0 is

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    Select the correct statement

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    The shortest and longest wave number in H spectrum of Lyman series is (R equalsRydberg constant)

    The shortest and longest wave number in H spectrum of Lyman series is (R equalsRydberg constant)

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    The line spectrum of two elements is not identical because

    The line spectrum of two elements is not identical because

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    How many electrons in an atom with atomic number 105 can have open parentheses n plus l close parentheses equals 8 ?

    How many electrons in an atom with atomic number 105 can have open parentheses n plus l close parentheses equals 8 ?

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    A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s

    A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s

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    T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank

    T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank

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    I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma where z is a complex number, then the value of open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text  is end text

    I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma where z is a complex number, then the value of open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text  is end text

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    T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s

    T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s

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    T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s

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    The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

    For such questions, we should be careful about the limits on variable.

    The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

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    For such questions, we should be careful about the limits on variable.

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    T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas  end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals

    T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas  end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals

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    T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s

    T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s

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    The number of solutions of the equation
    sin 2x = [1 + sin 2x] + [1 cos 2x] in open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square bracketswhere [.] is the greatest
    integer function is

    The number of solutions of the equation
    sin 2x = [1 + sin 2x] + [1 cos 2x] in open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square bracketswhere [.] is the greatest
    integer function is

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    If c o s invisible function application x c o s invisible function application 2 x c o s invisible function application 4 x c o s invisible function application 8 x equals fraction numerator cosec invisible function application x over denominator 16 end fraction, then

    If c o s invisible function application x c o s invisible function application 2 x c o s invisible function application 4 x c o s invisible function application 8 x equals fraction numerator cosec invisible function application x over denominator 16 end fraction, then

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