Chemistry-
General
Easy
Question
The ratio of the electron in second excited state of He+ ion to the electron in the first excited state of Be3+ is
- 1:3
- 9:16
- 1:9
- 16:9
The correct answer is: 1:9
En = eV
2nd excited state of He+ n = 3, Z = 2 for He+
E3 = =
1st excited state of Be3+ is n = 2 and Z = 4 for Be3+
E2 = =
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