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Chemistry-

General

Easy

Question

when treated with two equivalents of sodium in dry ether gives:

The correct answer is:

Related Questions to study

the major product formed in the following reaction,
is:

the major product formed in the following reaction,
is:

Chemistry-General

Which of the following is liquid at room .temperature?

Which of the following is liquid at room .temperature?

Chemistry-General

$stack L t with x rightwards arrow 1 below open square brackets fraction numerator x to the power of 3 end exponent plus 2 x to the power of 2 end exponent plus x plus 1 over denominator x to the power of 2 end exponent plus 2 x plus 3 end fraction close square brackets to the power of fraction numerator 1 minus cos invisible function application left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis to the power of 2 end exponent end fraction end exponent$ is

$stack L t with x rightwards arrow 1 below open square brackets fraction numerator x to the power of 3 end exponent plus 2 x to the power of 2 end exponent plus x plus 1 over denominator x to the power of 2 end exponent plus 2 x plus 3 end fraction close square brackets to the power of fraction numerator 1 minus cos invisible function application left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis to the power of 2 end exponent end fraction end exponent$ is

parallel

$stack L t with x rightwards arrow 2 below open parentheses fraction numerator x to the power of 3 end exponent minus 4 x over denominator x to the power of 3 end exponent minus 8 end fraction close parentheses to the power of negative 1 end exponent minus open parentheses fraction numerator x plus square root of 2 x end root over denominator x minus 2 end fraction minus fraction numerator square root of 2 over denominator square root of x minus square root of 2 end fraction close parentheses to the power of negative 1 end exponent$ is

$stack L t with x rightwards arrow 2 below open parentheses fraction numerator x to the power of 3 end exponent minus 4 x over denominator x to the power of 3 end exponent minus 8 end fraction close parentheses to the power of negative 1 end exponent minus open parentheses fraction numerator x plus square root of 2 x end root over denominator x minus 2 end fraction minus fraction numerator square root of 2 over denominator square root of x minus square root of 2 end fraction close parentheses to the power of negative 1 end exponent$ is

$stack l i m with x rightwards arrow infinity below fraction numerator left parenthesis x plus 1 right parenthesis to the power of 10 end exponent plus left parenthesis x plus 2 right parenthesis to the power of 10 end exponent plus... plus left parenthesis x plus 100 right parenthesis to the power of 10 end exponent over denominator x to the power of 10 end exponent plus 1 0 to the power of 10 end exponent end fraction$ is equal to

$stack l i m with x rightwards arrow infinity below fraction numerator left parenthesis x plus 1 right parenthesis to the power of 10 end exponent plus left parenthesis x plus 2 right parenthesis to the power of 10 end exponent plus... plus left parenthesis x plus 100 right parenthesis to the power of 10 end exponent over denominator x to the power of 10 end exponent plus 1 0 to the power of 10 end exponent end fraction$ is equal to

Let $f left parenthesis x right parenthesis equals fraction numerator log invisible function application left parenthesis 1 plus x plus x to the power of 2 end exponent right parenthesis plus log invisible function application left parenthesis 1 minus x plus x to the power of 2 end exponent right parenthesis over denominator sec invisible function application x minus cos invisible function application x end fraction$ , x $not equal to$ 1. The value of f(0) so that f is continuous at x = 0 is

Let $f left parenthesis x right parenthesis equals fraction numerator log invisible function application left parenthesis 1 plus x plus x to the power of 2 end exponent right parenthesis plus log invisible function application left parenthesis 1 minus x plus x to the power of 2 end exponent right parenthesis over denominator sec invisible function application x minus cos invisible function application x end fraction$ , x $not equal to$ 1. The value of f(0) so that f is continuous at x = 0 is

parallel

$stack l i m with x rightwards arrow 1 below fraction numerator left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of 2 n end exponent right parenthesis over denominator left square bracket left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of n end exponent right parenthesis right square bracket to the power of 2 end exponent end fraction$ is

$stack l i m with x rightwards arrow 1 below fraction numerator left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of 2 n end exponent right parenthesis over denominator left square bracket left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of n end exponent right parenthesis right square bracket to the power of 2 end exponent end fraction$ is

A function f(x) is defined as below $f left parenthesis x right parenthesis equals fraction numerator cos invisible function application left parenthesis sin invisible function application x right parenthesis minus cos invisible function application x over denominator x to the power of 2 end exponent end fraction comma x not equal to 0$ , f(0) = a, f(x) is continuous at x = 0 if a equals

A function f(x) is defined as below $f left parenthesis x right parenthesis equals fraction numerator cos invisible function application left parenthesis sin invisible function application x right parenthesis minus cos invisible function application x over denominator x to the power of 2 end exponent end fraction comma x not equal to 0$ , f(0) = a, f(x) is continuous at x = 0 if a equals

If A and B are two independent events, then A and $stack B with ̄ on top$ are

If A and B are two independent events, then A and $stack B with ̄ on top$ are

parallel

Let $a comma b$ and $c$ be non-zero vectors such that $left parenthesis a cross times b right parenthesis cross times c equals fraction numerator 1 over denominator 3 end fraction vertical line b vertical line vertical line c vertical line a.$ If q is the acute angle between the vectors $b$ and $c$ , then $sin invisible function application theta$ equals

Let $a comma b$ and $c$ be non-zero vectors such that $left parenthesis a cross times b right parenthesis cross times c equals fraction numerator 1 over denominator 3 end fraction vertical line b vertical line vertical line c vertical line a.$ If q is the acute angle between the vectors $b$ and $c$ , then $sin invisible function application theta$ equals

If $vertical line a cross times b vertical line equals 4$ and $vertical line a. b vertical line equals 2$ , then $vertical line a vertical line to the power of 2 end exponent vertical line b vertical line to the power of 2 end exponent equals$

If $vertical line a cross times b vertical line equals 4$ and $vertical line a. b vertical line equals 2$ , then $vertical line a vertical line to the power of 2 end exponent vertical line b vertical line to the power of 2 end exponent equals$

Let u = i + j, v = i – j and w = i + 2j + 3k. If n is a unit vector such that u.n = 0 and v.n = 0 then $vertical line w. n vertical line$ is equal to

Let u = i + j, v = i – j and w = i + 2j + 3k. If n is a unit vector such that u.n = 0 and v.n = 0 then $vertical line w. n vertical line$ is equal to

parallel

Angle between the line $r equals left parenthesis i plus 2 j minus k right parenthesis plus lambda rightwards arrow over short leftwards arrow left parenthesis i minus j plus k right parenthesis$ and the normal to the plane $r. left parenthesis 2 i minus j plus k right parenthesis equals 4$ is

Angle between the line $r equals left parenthesis i plus 2 j minus k right parenthesis plus lambda rightwards arrow over short leftwards arrow left parenthesis i minus j plus k right parenthesis$ and the normal to the plane $r. left parenthesis 2 i minus j plus k right parenthesis equals 4$ is

$left square bracket left parenthesis a cross times b right parenthesis cross times left parenthesis b cross times c right parenthesis left parenthesis b cross times c right parenthesis cross times left parenthesis c cross times a right parenthesis left parenthesis c cross times a right parenthesis cross times left parenthesis a cross times b right parenthesis right square bracket equals$

$left square bracket left parenthesis a cross times b right parenthesis cross times left parenthesis b cross times c right parenthesis left parenthesis b cross times c right parenthesis cross times left parenthesis c cross times a right parenthesis left parenthesis c cross times a right parenthesis cross times left parenthesis a cross times b right parenthesis right square bracket equals$

If $u equals 2 i plus 2 j minus k$ and $v equals 6 i minus 3 j plus 2 k comma$ then a unit vector perpendicular to both u and v is

If $u equals 2 i plus 2 j minus k$ and $v equals 6 i minus 3 j plus 2 k comma$ then a unit vector perpendicular to both u and v is

parallel

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