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Chemistry-

General

Easy

Question

Which one of the following sets of quantum number represents an impossible arrangement?

The correct answer is:

For every value of $l comma m$ can be from $negative l$ to $plus l$ through 0(zero). For $l equals 2 comma m$ cannot be $negative 3$

Related Questions to study

The number of spherical nodes in $4 s$ orbital is

The number of spherical nodes in $4 s$ orbital is

Chemistry-General

An orbital with $l equals 0$ is

An orbital with $l equals 0$ is

Chemistry-General

Select the correct statement

Select the correct statement

Chemistry-General

parallel

The shortest and longest wave number in H spectrum of Lyman series is ( $R equals$ Rydberg constant)

The shortest and longest wave number in H spectrum of Lyman series is ( $R equals$ Rydberg constant)

Chemistry-General

The line spectrum of two elements is not identical because

The line spectrum of two elements is not identical because

Chemistry-General

How many electrons in an atom with atomic number 105 can have $open parentheses n plus l close parentheses equals 8 ?$

How many electrons in an atom with atomic number 105 can have $open parentheses n plus l close parentheses equals 8 ?$

Chemistry-General

parallel

$A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s$

$A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s$

$T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank$

$T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank$

$I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma$ where z is a complex number, then the value of $open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text is end text$

$I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma$ where z is a complex number, then the value of $open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text is end text$

parallel

$T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s$

$T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s$

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s$

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s$

The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

For such questions, we should be careful about the limits on variable.

The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

For such questions, we should be careful about the limits on variable.

parallel

$T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals$

$T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals$

$T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s$

$T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s$

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

parallel

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