Chemistry-
General
Easy
Question
Which salt can be used to identify coloured cation?
- Borax
- Microcosmic salt
- Both (a) and (b)
- None of these
The correct answer is: Both (a) and (b)
Related Questions to study
Chemistry-
Which will give
on heating?
Which will give
on heating?
Chemistry-General
Chemistry-
Some of alkali metal salts are coloured.
yellow,
pink,
green. It is due to
Some of alkali metal salts are coloured.
yellow,
pink,
green. It is due to
Chemistry-General
Maths-
The equation of the hyperbola whose foci are (6, 4) and (–4, 4) and eccentricity 2 is given by
The equation of the hyperbola whose foci are (6, 4) and (–4, 4) and eccentricity 2 is given by
Maths-General
Chemistry-
Mg and Li are similar in their properties due to
Mg and Li are similar in their properties due to
Chemistry-General
Chemistry-
When an electron makes a transition from
state to
state, the frequency of emitted radiations is related to
according to ![left parenthesis n much greater-than 1 right parenthesis](data:image/png;base64,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)
When an electron makes a transition from
state to
state, the frequency of emitted radiations is related to
according to ![left parenthesis n much greater-than 1 right parenthesis](data:image/png;base64,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)
Chemistry-General
Chemistry-
The binding energy of an element is 64 Mev. If BE/nucleon is 6.4, then the number of nucleons are
The binding energy of an element is 64 Mev. If BE/nucleon is 6.4, then the number of nucleons are
Chemistry-General
Chemistry-
The ionization potential hydrogen atom is
. The energy required to remove an electron in the
state of the hydrogen atom is
The ionization potential hydrogen atom is
. The energy required to remove an electron in the
state of the hydrogen atom is
Chemistry-General
Chemistry-
In nuclear reaction,
The mass loss is nearly 0.02 amu. Hence, the energy released (in units of million kcal/mol) in the process is approximately
In nuclear reaction,
The mass loss is nearly 0.02 amu. Hence, the energy released (in units of million kcal/mol) in the process is approximately
Chemistry-General
Chemistry-
There are
of
and
of
in a rock. If
of
is
age of the rock is
There are
of
and
of
in a rock. If
of
is
age of the rock is
Chemistry-General
Maths-
The latus-rectum of the hyperbola
, is
The latus-rectum of the hyperbola
, is
Maths-General
Maths-
Let
and
. If
is a vector such that
=
and the angle between
and
is 300, then find the value of
.
Let
and
. If
is a vector such that
=
and the angle between
and
is 300, then find the value of
.
Maths-General
Maths-
The equation of the line passing through the point (1, -2, 3) and parallel to the line x – y + 2z = 5 and 3x + y + z = 6 is
The equation of the line passing through the point (1, -2, 3) and parallel to the line x – y + 2z = 5 and 3x + y + z = 6 is
Maths-General
Maths-
If (1 + x + x2)n = a0 + a1x + a2x2 + ………+a2nx2n, then the value of the determinant
is always
If (1 + x + x2)n = a0 + a1x + a2x2 + ………+a2nx2n, then the value of the determinant
is always
Maths-General
Maths-
India play two matches each with West Indies and Australia .In any match the probabilities of India getting points 0, 1 and 2 are 0.45, 0.05 and 0.50 respectively. Assuming that the outcomes are independent, the probability of India getting at least 7 points is
India play two matches each with West Indies and Australia .In any match the probabilities of India getting points 0, 1 and 2 are 0.45, 0.05 and 0.50 respectively. Assuming that the outcomes are independent, the probability of India getting at least 7 points is
Maths-General
Maths-
If the eccentricities of the hyperbolas
and
be e and
, then ![fraction numerator 1 over denominator e to the power of 2 end exponent end fraction plus fraction numerator 1 over denominator e subscript 1 end subscript superscript 2 end superscript end fraction equals](data:image/png;base64,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)
If the eccentricities of the hyperbolas
and
be e and
, then ![fraction numerator 1 over denominator e to the power of 2 end exponent end fraction plus fraction numerator 1 over denominator e subscript 1 end subscript superscript 2 end superscript end fraction equals](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAFYAAAAtCAYAAAA0s5z1AAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAXQ/cXWQAAAUlJREFUeNrtmzFKA0EYhQeLlIJFCLYiEryAWITcIJcQLKxsLbxArpFOLIO9hBRpgoSQ3huIlYiwvpG/CCEhMcyE+ZPvwWPZrT7e/vtmd9kN4X+6kB/lt1C+PLGGnnwrV7DmUQUrsAQLK8ECS7CwEiywBAtrtcSwosMUE0WwBJuzr930d7XPE5PDOaZg16xUAVXA4kWwBLuHC963PJTPYU2rI/lOHsOaR1+wpldbfoU1rU6tt85gTaf4KU/fgGFNePZf5GMnk1oMa0N+tqJ/t26aVwRtFhKcG9Z4Zidyx/Yv5ekGz9CwrlFXflg4FvupVuBl7oY13kR/yPWFY5+2hXVLXa24dIYFTqsn1r+uenJys++JNVzLI1jzaCbfW0+d2OLQcs5axH8J8ZFvIP8Y+E3BQ7Apq8v/EjyJYAmWYBHBEizBEuiO3nD9Apm8yyr4eB/eAAAA13RFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtZnJhYz48bW4+MTwvbW4+PG1zdXA+PG1pPmU8L21pPjxtbj4yPC9tbj48L21zdXA+PC9tZnJhYz48bW8+KzwvbW8+PG1mcmFjPjxtbj4xPC9tbj48bXN1YnN1cD48bWk+ZTwvbWk+PG1uPjE8L21uPjxtbj4yPC9tbj48L21zdWJzdXA+PC9tZnJhYz48bW8+PTwvbW8+PC9tYXRoPk3QrugAAAAASUVORK5CYII=)
Maths-General