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    Chemistry-
    General
    Easy

    Question

    Which will give tertiary butyl alcohol, when treated with Grignard’s reagent

    1. CH3MgBr + C subscript 2 end subscript H subscript 5 end subscript minus stack C with table row cell O end cell row cell vertical line vertical line end cell end table on top minus O C subscript 2 end subscript H subscript 5 end subscript    
    2. C2H5MgBr + C H subscript 3 end subscript minus stack C with table row cell O end cell row cell vertical line vertical line end cell end table on top minus C H subscript 3 end subscript    
    3. CH3MgBr + C H subscript 3 end subscript minus stack C with table row cell O end cell row cell vertical line vertical line end cell end table on top minus O C H subscript 3 end subscript    
    4. CH3MgBr + C H subscript 3 end subscript. C H subscript 2 end subscript minus stack C with table row cell O end cell row cell vertical line vertical line end cell end table on top minus H    

    The correct answer is: CH3MgBr + C H subscript 3 end subscript minus stack C with table row cell O end cell row cell vertical line vertical line end cell end table on top minus O C H subscript 3 end subscript

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    A compound ‘A’ forms ‘B’ with sodium metal and again ‘A’ forms ‘C’ with PCl5, but ‘B’ and ‘C’ form diethyl ether. Therefore ‘A’, ‘B’ and ‘C’ are respectively

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    In the reaction, C H subscript 3 end subscript C identical to C to the power of minus end exponent N a to the power of plus end exponent plus open parentheses C H subscript 3 end subscript close parentheses subscript 2 end subscript C H C l ⟶, the product formed is :

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