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Mathematics

Grade9

Easy

Question

Find the area of the following trapezoid:

$\frac{125 + 125 \sqrt{3} m^{2}}{2}$
$\frac{125 + 25 \sqrt{2} m^{2}}{3}$
$\frac{125 + 25 \sqrt{3} m^{2}}{2}$
$\frac{25 + 125 \sqrt{3} m^{2}}{2}$

The correct answer is: $fraction numerator 125 plus 25 square root of 3 m squared over denominator 2 end fraction$

Area of a trapezoid = ½ x sum of parallel sides x distance between them.
In this question, the distance between them is not given.
Area of the trapezoid = 1/2x(10 + 15 + 5√3 ) x 5 = (25 + 5√3) x 5/2
= (125 + 25√3)/2 sq m

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