Find the slope of the line perpendicular to line h and passing through point P .

$\frac{1}{3}$
-3
3
-1

hint Hint:

We know that the product of slope of two perpendicular lines are -1. So to find the line perpendicular to h first we will find the slope of h, by $fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction$ .

The correct answer is: $1 third$

Slope of line h, passing through the point (3,4) and (5,-2), m = $fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction$
$equals fraction numerator negative 2 minus 4 over denominator 5 minus 3 end fraction equals fraction numerator negative 6 over denominator 2 end fraction equals negative 3$
Slope of the line perpendicular to h = $fraction numerator negative 1 over denominator m end fraction$
= $1 third$

Find the measure of $angle A C D$ .

MathematicsGrade9

Grade9

Mathematics

Line x passes through (2,3) and (7, -1). Line y passes through (5, 4) and (-3,2). Which line is steeper, x or y?

MathematicsGrade9

Grade9

Mathematics

If l || m then find the measures of x and y?

In this question we have to find x and y given that l is parallel to m and t is the transversal. First to find x we can use linear pair as we know that the sum of angles which are in linear pair is 180 deg. Next to find y we can use the theorem alternate exterior angles are equal.