Given two triangles are similar. Which is the similarity criteria it satisfies?

If two triangles UBC ~ UST, then find the value of BS.

$capital delta HGF tilde capital delta HTS$ satisfies which similarity criteria?

$angle S T H equals space angle F G H comma space angle T H S equals space angle G H F comma$ then by AA similarity criteria

$capital delta HGF tilde capital delta HTS$ satisfies which similarity criteria?

$angle S T H equals space angle F G H comma space angle T H S equals space angle G H F comma$ then by AA similarity criteria

If an angle of one triangle is congruent to an angle of a second triangle and the lengths of the sides, including these angles, are proportional, it satisfies

If triangles ABC and ADE are similar, then which of the following is not true?

In the given figure, two triangles are similar, then it satisfies

In the given figure, two triangles are similar $angle A equals angle D$ and $fraction numerator D E over denominator A B end fraction equals fraction numerator D F over denominator A C end fraction$ , then it satisfies

$angle A equals angle D$ and $fraction numerator D E over denominator A B end fraction equals fraction numerator D F over denominator A C end fraction$ , given; therefore, SAS similarity criteria

In the given figure, two triangles are similar $angle A equals angle D$ and $fraction numerator D E over denominator A B end fraction equals fraction numerator D F over denominator A C end fraction$ , then it satisfies

$angle A equals angle D$ and $fraction numerator D E over denominator A B end fraction equals fraction numerator D F over denominator A C end fraction$ , given; therefore, SAS similarity criteria

In the given figure, two triangles are similar as they satisfy

$angle B E A equals angle C E D$ and $fraction numerator B E over denominator E D end fraction equals fraction numerator A E over denominator E C end fraction$ , then by SAS similarity criteria

In the given figure, two triangles are similar as they satisfy

$angle B E A equals angle C E D$ and $fraction numerator B E over denominator E D end fraction equals fraction numerator A E over denominator E C end fraction$ , then by SAS similarity criteria

In the given figure, two triangles are similar as they satisfy

In similar triangles, if the corresponding side lengths of two triangles are proportional, it satisfies

In similar triangles, if two angles of one triangle are congruent to two angles of another triangle, it satisfies