Mathematics
Grade-8
Easy

Question

How many solutions do the following equations have?
y = x + 3 and y = x + 1

  1. No solution
  2. Two solution
  3. Three solutions
  4. Infinite solutions

hintHint:

When two or more linear equations interact, we have a system of linear equations. There are three systems of the equation:
  • No solution: System with parallel lines
  • One solution: System with intersecting lines
  • Infinitely many solutions: System with coinciding lines
Here in this question, we have given two equations where we have to find which system it belongs to and how many solutions it has.

The correct answer is: No solution


    The value or values that hold true for each equation in the system constitute the solution to the system of equations. In this question we have given two equations, those are:
    space y space equals space x space plus space 3
y space equals space x space plus space 1
    We have to find how many solutions it has. Let's first re-arrange the terms, we get:
    x minus y equals negative 3
x minus y equals negative 1
N o w space c o m p a r i n g space i t comma space w e space g e t colon
1 over 1 equals fraction numerator negative 1 over denominator negative 1 end fraction not equal to fraction numerator negative 3 over denominator negative 1 end fraction
1 over 1 equals 1 over 1 not equal to 3 over 1
S o space b e c a u s e space a 1 divided by a 2 equals b 1 divided by b 2 not equal to c 1 divided by c 2 comma space s o space t h e s e space a r e space p a r a l l e l space l i n e s.
    So these equations have no solution.

    So here we have given two equations,  y = x + 3 and y = x + 1 and we had to find out how many solutions it have. Using the concept we found out that the system is having parallel lines and hence it has no solution.

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