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If space space lambda italic space space be space the space ratio space of space the space roots space of space the space quadratic space equation space in space straight x comma 3 m squared x squared plus m left parenthesis m minus 4 right parenthesis x plus 2 equals 0 space space
then space space the space least space value space of space space straight m space space for space which space space lambda plus 1 over lambda equals 1 space space is

  1. 2 minus square root of 3
  2. 4 minus 3 square root of 2
  3. negative 2 plus square root of 2
  4. 4 minus 2 square root of 3

The correct answer is: 4 minus 3 square root of 2


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