Question
The point on an angle bisector is ____ from the two sides of the angle.
- Perpendicular
- Parallel
- Half the distance
- Equidistant
The correct answer is: Equidistant
The point on an angle bisector is equidistant from the two sides of the angle
Related Questions to study
The point at which the angle bisectors intersect in a triangle is ____ from the ____ of the triangle.
The point at which the angle bisectors intersect is equidistant from the sides of the triangle.
The point at which the angle bisectors intersect in a triangle is ____ from the ____ of the triangle.
The point at which the angle bisectors intersect is equidistant from the sides of the triangle.
What is the perimeter of the triangle?
What is the perimeter of the triangle?
In the given figure, 
, a person must start from home and reach school, grocery store and reach home. The road is in a circular path.
Which concept is used to solve this problem?
In the given figure, , a person must start from home and reach school, grocery store and reach home. The road is in a circular path.
Which concept is used to solve this problem?
In the given figure, what is the point of concurrency?
In the given figure, what is the point of concurrency?
In the given figure, what is the perimeter of PDE?
In the given figure, what is the perimeter of PDE?
Find x. 
Find x.
Find x.
Find x.
Find x.
From angle bisector theorem, x = 
>Therefore, the value of x is 22 degrees.
Find x.
From angle bisector theorem, x =
>Therefore, the value of x is 22 degrees.
In the given figure P is the incenter, find PD
To obtain the radius of the incircle, we know that the points D, E, F are the perpendicular bisector points. Hence, the angle must be 90 degrees. We can now apply Pythagorean theorem to obtain the unknown values.
In the given figure P is the incenter, find PD
To obtain the radius of the incircle, we know that the points D, E, F are the perpendicular bisector points. Hence, the angle must be 90 degrees. We can now apply Pythagorean theorem to obtain the unknown values.
If a circle is drawn through the point of concurrency of given figure, find the radius of the circle.
The points of concurrency are D, E, F then P becomes the center of the circle and that circle generally called as a incircle of a triangle. Radius of incircle can be found easily applying the Pythagorean theorem to any one of the triangle.
>>>>
>>>PE = 3 units.
If a circle is drawn through the point of concurrency of given figure, find the radius of the circle.
The points of concurrency are D, E, F then P becomes the center of the circle and that circle generally called as a incircle of a triangle. Radius of incircle can be found easily applying the Pythagorean theorem to any one of the triangle.
>>>>
>>>PE = 3 units.
Find MP in the given figure.
Always angular bisector divides the given angle into 2 equal parts. Then, by equalizing the the two equations we can get the measure of angles easily.
Find MP in the given figure.
Always angular bisector divides the given angle into 2 equal parts. Then, by equalizing the the two equations we can get the measure of angles easily.
Find ∠DAC in the given figure.
For such questions, we should know the properties of the angle bisector.
Find ∠DAC in the given figure.
For such questions, we should know the properties of the angle bisector.
Identify the theorem used to solve the problem.
Identify the theorem used to solve the problem.
In a scalene triangle, the incenter lies ____.
In a scalene triangle, the incenter lies ____.
If P is equidistant from all the sides of the triangle ABC, then a circle drawn with P as the center touching all the sides, then the center of the circle is also called ______.
For such questions, we should know about the different centers of the circle and triangle.
If P is equidistant from all the sides of the triangle ABC, then a circle drawn with P as the center touching all the sides, then the center of the circle is also called ______.
For such questions, we should know about the different centers of the circle and triangle.
