Mathematics
Grade-8
Easy
Question
Solve the equation 6 – 6x = 5x – 9x – 2.
- 4
- 5
- 6
- 7
Hint:
An equation has a constant, variable and an equal to sign. It has two sides LHS and RHS. A linear equation in one variable is equation with only one variable and in which the highest degree is 1. Here, we have to find the value of unknown value, i.e., x by operating both sides with the same number so that the equation will be balanced.
The correct answer is: 4
In the given question the equation is 6 – 6x = 5x – 9x – 2.
Here, we have to find the solution of the given linear equation in one variable.
Bring all the terms containing variables in one side by operating same numbers on both sides to balance the equation.
Step 1: Add 6x on both sides.
6-6x+6x= 5x- 9x-2+6x
6= 5x-9x-2+6x
Step 2: Add 2 on both sides.
6+2= 5x-9x-2+6x+2
6+2= 5x-9x+6x
8= 5x-9x+6x
Step 3: Solve the RHS.
8= 2x
Step 4: Divide both sides by 2.
![rightwards double arrow 8 over 2 equals fraction numerator 2 x over denominator 2 end fraction
rightwards double arrow 4 equals x
rightwards double arrow x equals 4](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAFQAAABTCAYAAAABbiB5AAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAApgpYK8gAAAwtJREFUeNrtnD9oU1EUxh9FipQgiIhIh4J0KB26OJUiUpDSwUEEB3GSLh1EHNwcpdBBOkiXIp2kFEoppYgURMShgyClOHTrUDq4S4eQJX4XTyA8Xt67N7nv3nPj94MP8pqQHk7uv+Q752VZOMag99Al1IQOofEsPHPQLvQHakEn0LMsQTahFegKNAqtQj8ixPEdego15HoaOpK/JUUzdz0iI0QDE9Cv1BJ62TUqOgm9UPyBG5ZkJuV5K89FxayfL7uuZ6F3SpI5K9O+iGPoVtf1c2hdQ9AzMsVbso79hu4piOuqrOVzPZ5fhNbk8QPoq5Y1agu6LRuS4S50JomOxXVoH1qoeN0X6L6cCG5oSOhej8TNQ98ixXRHkjlp8dpXMrNmMiU0+3yuLqagD3I2tj23rmk6Wp32GAnTspaGxGwwO3IethnFB5J4c0L5qWXKP5akzstxaUQemzV0OXAsn2SEVnET+pxL4EPoo5ZR+kSOIC2Z5manfxQhjnaJOozKul/01Xhbdn5C/gNeQ9eYBn+8gc5LvlXEWvvya6Aq2pZakd2aeGBTkrrl4YMJMcraATTwP18NPEKTnfJa19Ch3eUbTAMhpJwUrNuk7OUUrNvk7eUUrNvk7OUmY/RHmXXLGB2psm4ZowO21i1jtMDFumWMFbhYt4yxAhfrljFaYGvdMkZLUvgNc6h+ZyWEEEIIIYQQQoguTLE/f2TwhPG5T5lQf2xk/zp3mdACXGvsjWPYaTatM6Gq27DLcKkPNb0+pupiwjKhgxbUqm3D9lVjb0bMi9z71onKNmxbqmrsTdfuUcEHVTfq2rBdRmhZjb2puJh0TKiPGnp1bdi+1tAYzQUq27BtdvnGACO/LtS2Yde9lNSB+jbslBLKNmxCCCGEEEIIIYSQAlgH4BHWAXgmqToAF18+hlceqg7AG673bXL1ygcx6lzrAILh8953Ib3y0HUAXrG5912HEF55rDoAryPU9t53Ll55v1O+nzqAJNfQUF55sjcZdPHlY3vlQ3UO1eCVD01CtXjlURL6F8CxctNKfb8FAAABT3RFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtbz4mI3gyMUQyOzwvbW8+PG1mcmFjPjxtbj44PC9tbj48bW4+MjwvbW4+PC9tZnJhYz48bW8+PTwvbW8+PG1mcmFjPjxtcm93Pjxtbj4yPC9tbj48bWk+eDwvbWk+PC9tcm93Pjxtbj4yPC9tbj48L21mcmFjPjxtc3BhY2UgbGluZWJyZWFrPSJuZXdsaW5lIi8+PG1vPiYjeDIxRDI7PC9tbz48bW4+NDwvbW4+PG1vPj08L21vPjxtaT54PC9taT48bXNwYWNlIGxpbmVicmVhaz0ibmV3bGluZSIvPjxtbz4mI3gyMUQyOzwvbW8+PG1pPng8L21pPjxtbz49PC9tbz48bW4+NDwvbW4+PC9tYXRoPiJDQqwAAAAASUVORK5CYII=)
So, the solution of the equation is 4.
Therefore, the correct option is a,i.e., 4.
Like terms are the terms having same variable of same power in which the coefficient may not be the same whereas unlike terms are the terms which don't have same variable. Addition and subtraction are possible in like terms but not in unlike terms.
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