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Mathematics

Grade-11

Easy

Question

Solve the quadratic equation below using the Square Root Method.
$negative 3 x squared minus 6 equals negative x squared minus 12$

$\sqrt{2}$
$\sqrt{3}$
$- \sqrt{3}$
$- \sqrt{2}$

The correct answers are: $square root of 3$ , $negative square root of 3$

$negative 3 x squared minus 6 equals negative x squared minus 12$
$negative 3 x squared minus 6 plus 6 equals negative x squared minus 12 plus 6$
$negative 3 x squared equals negative x squared minus 6$
$negative 3 x squared plus x squared equals negative x squared plus x squared minus 6$
$negative 2 x squared equals negative 6$
$fraction numerator negative 2 x squared over denominator negative 2 end fraction equals fraction numerator negative 6 over denominator negative 2 end fraction$
$x squared equals 3$
$square root of x squared end root equals plus-or-minus square root of 3$
$x equals plus-or-minus square root of 3$

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