Question
What is the relation between ∠1 and ∠2 if AD = CD?
- ∠1 > ∠2
- ∠1 < ∠2
- ∠1 = ∠2
- ∠1 =
∠2
∠2
Hint:
ΔABD ≅ ΔCBD (RHS congruence criterion)
The correct answer is: ∠1 = ∠2
From figure, in ΔABD and ΔBCD,
∠BAD = ∠BCD = 90°
AQ = CD (given)
BD = BD (common side)
⇒ ΔABD ≅ ΔCBD (RHS congruence criterion)
⇒∠1 = ∠2 (Corresponding parts of congruent triangles)
∠BAD = ∠BCD = 90°
AQ = CD (given)
BD = BD (common side)
⇒ ΔABD ≅ ΔCBD (RHS congruence criterion)
⇒∠1 = ∠2 (Corresponding parts of congruent triangles)
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