Maths-
General
Easy
Question
From a solid wooden cylinder of 25 cm height and 6 cm diameter , two conical cavities are hollowed out , The diameters of the cones are also of 6 cm and the height is 10.5 cm, Find the volume of the remaining solid ?
Hint:
Volume of solid cylinder ![equals 1 third pi r squared h](data:image/png;base64,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)
The correct answer is: 508.93
Explanation:
- We have given From a solid wooden cylinder of 25 cm height and 6 cm diameter , two conical cavities are hollowed out , The diameters of the cones are also of 6 cm and the height is 10.5 cm
- We have to find the volume of the remaining solid.
Step 1 of 1:
Volume of the cylinder is
![table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell V equals pi r squared h end cell row cell equals pi left parenthesis 3 right parenthesis squared cross times 25 end cell row cell equals 225 pi end cell end table](data:image/png;base64,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)
Volume of both cone will be
![table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell V equals 2 cross times 1 third pi r squared h end cell row cell equals 2 cross times 1 third pi left parenthesis 3 right parenthesis squared cross times 10.5 end cell row cell equals 63 pi end cell end table](data:image/png;base64,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)
Volume of the remaining solid will be
![table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell equals 225 pi minus 63 pi end cell row cell equals 162 pi end cell row cell equals 508.93 cm cubed end cell end table](data:image/png;base64,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)
Related Questions to study
Maths-
From a solid circular cylinder of 5 cm radius and 12 cm height , a conical cavity of the same base radius and of the same height is hollowed out. Find the volume of the remaining solid ?
From a solid circular cylinder of 5 cm radius and 12 cm height , a conical cavity of the same base radius and of the same height is hollowed out. Find the volume of the remaining solid ?
Maths-General
Maths-
A hemispherical container of 4 cm radius is filled to the brim with milk . The milk is then poured in a vertical right circular cone of 8 cm radius and 16 cm height. What percentage of the vertical right circular cone remains empty ?
A hemispherical container of 4 cm radius is filled to the brim with milk . The milk is then poured in a vertical right circular cone of 8 cm radius and 16 cm height. What percentage of the vertical right circular cone remains empty ?
Maths-General
Maths-
An ice cream cone is in the union of a right circular cone and hemisphere that has the same base as the cone . Find the Volume of the ice cream if the height of the cone is 9 cm and radius of its base is 2.5 cm.
An ice cream cone is in the union of a right circular cone and hemisphere that has the same base as the cone . Find the Volume of the ice cream if the height of the cone is 9 cm and radius of its base is 2.5 cm.
Maths-General
Maths-
A Hemispherical bowl of 36 cm internal diameter contains a liquid. This liquid is to be filled into right circular cone shaped bottles of 3 cm radius and 18 cm height , How many bottles are required to empty the bowl ?
A Hemispherical bowl of 36 cm internal diameter contains a liquid. This liquid is to be filled into right circular cone shaped bottles of 3 cm radius and 18 cm height , How many bottles are required to empty the bowl ?
Maths-General
Maths-
A hemisphere of 5 cm radius surmounted by a right circular cone of 5 cm base radius. Find the volume of the solid correct to two places of decimals if the height of the cone is 7 cm.
A hemisphere of 5 cm radius surmounted by a right circular cone of 5 cm base radius. Find the volume of the solid correct to two places of decimals if the height of the cone is 7 cm.
Maths-General
Maths-
An inverted conical vessel of 6 cm radius and 8 cm height is completely filled with water. A Sphere is lowered into the water and its size is such that when it touches the sides , it is just immersed. What fraction of water overflows ?
An inverted conical vessel of 6 cm radius and 8 cm height is completely filled with water. A Sphere is lowered into the water and its size is such that when it touches the sides , it is just immersed. What fraction of water overflows ?
Maths-General
Maths-
A rectangle field is 34 m long and 15 m broad. Find the cost of
(a) ploughing the field at Rs 6 per square metre.
(b) fencing it at R s 9.50 per metre.
A rectangle field is 34 m long and 15 m broad. Find the cost of
(a) ploughing the field at Rs 6 per square metre.
(b) fencing it at R s 9.50 per metre.
Maths-General
Maths-
What is the least number of solid metallic spheres of 6 cm diameter that should be melted and recast to form a solid metal right circular cone whose height is 135 cm and diameter is 4 cm?
What is the least number of solid metallic spheres of 6 cm diameter that should be melted and recast to form a solid metal right circular cone whose height is 135 cm and diameter is 4 cm?
Maths-General
Maths-
A Hollow sphere of internal and external diameters of 6 cm and 10 cm respectively is melted into a cone of 8 cm base diameter . Find the height of the cone ?
A Hollow sphere of internal and external diameters of 6 cm and 10 cm respectively is melted into a cone of 8 cm base diameter . Find the height of the cone ?
Maths-General
Maths-
Find the area of a rectangle whose length is 10 m and breadth is 6 m.
Find the area of a rectangle whose length is 10 m and breadth is 6 m.
Maths-General
Maths-
The perimeter of a rectangular plot is 180 m and its area is 1800 sq.metre. Take the length of the plot as x m. Use the perimeter to write the value of the breadth in terms of x. Use the value of length , breadth and the area to write an equation in x. Solve the equation to calculate the length and breadth of the plot.
The perimeter of a rectangular plot is 180 m and its area is 1800 sq.metre. Take the length of the plot as x m. Use the perimeter to write the value of the breadth in terms of x. Use the value of length , breadth and the area to write an equation in x. Solve the equation to calculate the length and breadth of the plot.
Maths-General
Maths-
Find the area and perimeter of a rectangle whose l = 70mand b = 50m.
Find the area and perimeter of a rectangle whose l = 70mand b = 50m.
Maths-General
Maths-
A Conical tent is to accommodate 77 persons. Each person must have 16 cubic metre of air to breathe. Given the radius of the tent as 7 m. Find the height of the tent and also its C.S.A?
A Conical tent is to accommodate 77 persons. Each person must have 16 cubic metre of air to breathe. Given the radius of the tent as 7 m. Find the height of the tent and also its C.S.A?
Maths-General
Maths-
Find the breadth of a rectangle whose area is 144 m2 and length is 16 m. Also find its perimeter.
Find the breadth of a rectangle whose area is 144 m2 and length is 16 m. Also find its perimeter.
Maths-General
Maths-
The radius of the base of a circular cone Is halved. Keeping the height same , What is the ratio of the volume of the reduced cone to that of the original cone ?
The radius of the base of a circular cone Is halved. Keeping the height same , What is the ratio of the volume of the reduced cone to that of the original cone ?
Maths-General