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Maths-

General

Easy

Question

A car was listed with a price of $12,000. The price decreased by p% to $9600. What is the value of p ?

The correct answer is: 20

Given the original value = $12,000
The final value after P% decrement = $9,600
We get (100 - p)% of original value = The final value after P% decrement
(100 - p)% of 12,000 = 9,600
$fraction numerator left parenthesis 100 minus p right parenthesis over denominator 100 end fraction cross times 12 comma 000 equals 9 comma 600 not stretchy rightwards double arrow fraction numerator left parenthesis 100 minus p right parenthesis over denominator 100 end fraction equals 4 over 5$
$left parenthesis 100 minus p right parenthesis equals 100 cross times 4 over 5 not stretchy rightwards double arrow 100 minus p equals 80$
$p equals 100 minus 80 equals 20$
∴ P = 20

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