Maths-
General
Easy

Question

Ken is working this summer as part of a crew on a farm. He earned $8 per hour for the first 10 hours he worked this week. Because of his performance, his crew leader raised his salary to $10 per hour for the rest of the week. Ken saves 90% of his earnings from each week. What is the least number of hours he must work the rest of the week to save at least $270 for the week?

  1. 38
  2. 33
  3. 22
  4. 16

The correct answer is: 22


    HINT –  Form an inequality between total earnings and money saved every week
    SOLUTION - According to question, salary earned for first 10 hours in the
    week  =  $ 8 cross times 10
    =  $ 80
    Let work hours for the rest of the week = x
    Money earned for the rest of the week = $ 10 cross times x
    = $ 10x
    Total earnings of the week = $ 80 + 10 x
    Percentage of his earnings he saved every week = 90 %
    i.e. 90% of total earnings = money saved
    Since Ken saved atleast $ 270 in this week
    rightwards double arrow90% of (80 + 10x) ≥ 270
    rightwards double arrow(80 + 10x ) ≥ 270
    rightwards double arrow(80 + 10x ) ≥ 270
    rightwards double arrow9 (80 + 10x)  > 2700
    rightwards double arrow720 + 90x ≥ 2700
    rightwards double arrow90x ≥ 2700 - 720
    rightwards double arrow90x > 1980
    rightwards double arrowx  >  22
    So, no of hours he should at least work is 22 hours
    Hence, option C is correct

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