Find the axis of symmetry, vertex and y-intercept of the function
f(x) = -2x² + 4x - 3

The correct answer is: -3

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= -2x² + 4x -3, a= -2, b= 4, and c= -3. So, the equation for the axis of symmetry is given by

x = −(4)/2(-2)

x = -4/-4

x = 1
The equation of the axis of symmetry for f(x)= 2x² + 4x - 3 is x = 1.
The x coordinate of the vertex is the same:
h = 1
The y coordinate of the vertex is :

k = f(h)

k = -2(h)² + 4(h) - 3

k = -2(1)² + 4(1) - 3

k = -2 + 4 - 3

k = -1
Therefore, the vertex is (1 , -1)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.

y = -2(0)² + 4(0) - 3

y = 0 + 0 - 3

y = -3
Therefore, Axis of symmetry is x = 1
Vertex is ( 1 , -1)
Y- intercept is -3.