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Maths-

General

Easy

Question

The distance between the segment joining origin and (x, y) is

𝑥 − 𝑦
$\sqrt{x + y}$
$\sqrt{x^{2} + y^{2}}$
|𝑥 − 𝑦|

hint Hint:

Distance between two points having coordinates (x1, y1) and (x2, y2) is given by formula:
Distance = $square root of open parentheses x subscript 2 minus x subscript 1 close parentheses squared plus open parentheses y subscript 2 minus y subscript 1 close parentheses squared end root$
Coordinates of origin are (0, 0).

The correct answer is: $square root of x squared space plus space y squared end root$

Step by step explanation:

○        Given:
Points (0,0) and B (x, y).
○        Step 1:
○        Find distance:
○     Distance = $square root of open parentheses x subscript 2 minus x subscript 1 close parentheses squared plus open parentheses y subscript 2 minus y subscript 1 close parentheses squared end root$
Distance = $square root of left parenthesis x minus 0 right parenthesis squared plus left parenthesis y minus o right parenthesis squared end root$
$rightwards double arrow$ Distance = $square root of left parenthesis x right parenthesis squared plus left parenthesis y right parenthesis squared end root$
Hence, the distance between points is $square root of left parenthesis x right parenthesis squared plus left parenthesis y right parenthesis squared end root$ units.
●       Final Answer:
Correct option : C. $square root of left parenthesis x right parenthesis squared plus left parenthesis y right parenthesis squared end root$ units.

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