Find the axis of symmetry, vertex and y-intercept of the function
f(x) = 2x² + 8x + 2

The correct answer is: 2

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= 2x² + 8x + 2, a= 2, b= 8, and c= 2. So, the equation for the axis of symmetry is given by

x = −(8)/2(2)

x = -8/4

x = -2
The equation of the axis of symmetry for f(x)= 2x² + 8x + 2 is x = -2.
The x coordinate of the vertex is the same:

h = -2
The y coordinate of the vertex is :

k = f(h)

k = 2(h)² + 8(h) + 2

k = 2(-2)² + 8(-2) + 2

k = 8 – 16 + 2

k = -6
Therefore, the vertex is (-2 , -6)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.

y = 2(0)² + 8(0) + 2

y = 0 + 0 + 2

y = 2
Therefore, Axis of symmetry is x = -2
Vertex is ( -2 , -6)
Y- intercept is 2.