Graph f(x) = 0.25x² – 0.5x - 6. What are axis of symmetry, vertex and y-intercept of the function

The correct answer is: -6

                                

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= 0.25x² – 0.5x - 6, a= 0.25, b= -0.5, and c= -6. So, the equation for the axis of symmetry is given by
x = −(-0.5)/2(0.25)
x = 0.5/0.5
x = 1
The equation of the axis of symmetry for f(x)= = 0.25x² – 0.5x - 6 is x = 1.
The x coordinate of the vertex is the same:
h = 1
The y coordinate of the vertex is :
k = f(h)
k = 0.25(h)² – 0.5(h) - 6
k = 0.25(1)² – 0.5(1) - 6
k = 0.25 – 0.5 – 6
k = -6.25
Therefore, the vertex is (1 , -6.25)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.
y = 0.25(0)² – 0.5(0) - 6
y = 0 - 0 - 6
y = -6
Therefore, Axis of symmetry is x = 1
Vertex is ( 1 , -6.25)
Y- intercept is -6.