Maths-
General
Easy

Question

fraction numerator 2 space left parenthesis straight x space plus space 1 right parenthesis over denominator straight x space plus space 5 end fraction space equals space 1 space minus space fraction numerator 1 over denominator straight x space plus space 5 end fraction
What is the solution to the equation above?

  1. 0
  2. 2
  3. 3
  4. 5

The correct answer is: 2


    HINT :- Solve the given equation to find the solution to the above equation .
    Given , fraction numerator 2 left parenthesis straight x space plus space 1 right parenthesis over denominator straight x space plus space 5 end fraction space equals space 1 space minus space fraction numerator 1 over denominator straight x space plus space 5 end fraction space not stretchy rightwards double arrow space fraction numerator 2 left parenthesis straight x space plus space 1 right parenthesis over denominator straight x space plus space 5 end fraction space equals space fraction numerator straight x space plus space 5 space minus space 1 over denominator straight x space plus space 5 end fraction space not stretchy rightwards double arrow space fraction numerator 2 straight x space plus space 2 over denominator straight x space plus space 5 end fraction space equals space fraction numerator straight x space plus space 4 over denominator straight x space plus space 5 end fraction
    not stretchy rightwards double arrow space 2 straight x space plus space 2 space equals space straight x space plus space 4 where x ≠ -5
    not stretchy rightwards double arrow 2 straight x space minus space straight x space equals space 4 space minus space 2 space not stretchy rightwards double arrow space straight x space equals space 2
    x = 2 is the solution of given equation.

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