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Maths-

General

Easy

Question

A fair die is tossed three times. Given that the sum of the first two tosses equals the third. The probability that at least one ‘2’ has turned up, is equal to

$\frac{1}{6}$
$\frac{91}{216}$
$\frac{1}{2}$
$\frac{8}{15}$

The correct answer is: $fraction numerator 8 over denominator 15 end fraction$

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