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Question

$A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s$

$4 s q . u n i t s$
$2 s q . u n i t s$
$1 s q . u n i t s$
$\frac{1}{2} s q . u n i t s$

The correct answer is: $1 blank s q. blank u n i t s$

Related Questions to study

$T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank$

$T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank$

$I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma$ where z is a complex number, then the value of $open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text is end text$

$I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma$ where z is a complex number, then the value of $open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text is end text$

$T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s$

$T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s$

parallel

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s$

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s$

The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

For such questions, we should be careful about the limits on variable.

The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

For such questions, we should be careful about the limits on variable.

$T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals$

$T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals$

parallel

$T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s$

$T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s$

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

If $c o s invisible function application x c o s invisible function application 2 x c o s invisible function application 4 x c o s invisible function application 8 x equals fraction numerator cosec invisible function application x over denominator 16 end fraction$ , then

If $c o s invisible function application x c o s invisible function application 2 x c o s invisible function application 4 x c o s invisible function application 8 x equals fraction numerator cosec invisible function application x over denominator 16 end fraction$ , then

parallel

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank open parentheses i n blank s q. blank u n i t s close parentheses comma blank i n blank t h e blank f i r s t blank q u a d r a n t comma blank b o u n d e d blank b y blank t h e blank p a r a b o l a blank y equals 9 x to the power of 2 end exponent blank a n d blank t h e blank l i n e s blank x equals 0 comma y equals 1 blank a n d blank y equals 4 blank i s colon$

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank open parentheses i n blank s q. blank u n i t s close parentheses comma blank i n blank t h e blank f i r s t blank q u a d r a n t comma blank b o u n d e d blank b y blank t h e blank p a r a b o l a blank y equals 9 x to the power of 2 end exponent blank a n d blank t h e blank l i n e s blank x equals 0 comma y equals 1 blank a n d blank y equals 4 blank i s colon$

Number of solutions of the equation Sin x + sin²x + sin³ x + sin⁴x + ……. Π= 2 where x Π[0,4Π], is

Number of solutions of the equation Sin x + sin²x + sin³ x + sin⁴x + ……. Π= 2 where x Π[0,4Π], is

The number of real solutions of the equation $s i n invisible function application open parentheses fraction numerator pi x over denominator 2 square root of 3 end fraction close parentheses equals x to the power of 2 end exponent minus 2 square root of 3 x plus 4$ is

The number of real solutions of the equation $s i n invisible function application open parentheses fraction numerator pi x over denominator 2 square root of 3 end fraction close parentheses equals x to the power of 2 end exponent minus 2 square root of 3 x plus 4$ is

parallel

For which of the following values of m is the area of the region bounded by the curve y =x - $blank x to the power of 2 end exponent blank$ and the line y = mx equal to 9/2…

For which of the following values of m is the area of the region bounded by the curve y =x - $blank x to the power of 2 end exponent blank$ and the line y = mx equal to 9/2…

The area of the region bounded by y = $blank open vertical bar x close vertical bar minus 1 blank$ and y =- $open vertical bar x close vertical bar$ +1 is…

The area of the region bounded by y = $blank open vertical bar x close vertical bar minus 1 blank$ and y =- $open vertical bar x close vertical bar$ +1 is…

Which of the following is the correct order of stability of the following compound?
I)
II)
III)

Which of the following is the correct order of stability of the following compound?
I)
II)
III)

Chemistry-General

parallel

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