Maths-
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Easy

Question

Assertion : In a ABC, fraction numerator a cos invisible function application A plus b cos invisible function application B plus c cos invisible function application C over denominator a plus b plus c end fraction is equal to fraction numerator r over denominator R end fraction
Reason : In equilateral triangle the ratio between In-radius and circum-radius is 1 : 2.

  1. If both (A) and (R) are true, and (R) is the correct explanation of (A).  
  2. If both (A) and (R) are true but (R) is not the correct explanation of (A).  
  3. If (A) is true but (R) is false.  
  4. If (A) is false but (R) is true.  

The correct answer is: If both (A) and (R) are true but (R) is not the correct explanation of (A).

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Assertion : In any triangle ABC, fraction numerator 1 over denominator a b end fraction plus fraction numerator 1 over denominator b c end fraction plus fraction numerator 1 over denominator c a end fraction equals fraction numerator 1 over denominator 2 r R end fraction, where r is in radius and R is circum radius.
Reason : R  2r.

Assertion : In any triangle ABC, fraction numerator 1 over denominator a b end fraction plus fraction numerator 1 over denominator b c end fraction plus fraction numerator 1 over denominator c a end fraction equals fraction numerator 1 over denominator 2 r R end fraction, where r is in radius and R is circum radius.
Reason : R  2r.

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