Maths-
General
Easy

Question

Calculate the area of equilateral triangle whose height is 25 cm

hintHint:

Since it’s an equilateral triangle so all angles are equal to 60°.

The correct answer is: 1.73


    It is given that height, h = 25 cm
    Let AB = x
    We know that all angles are equal to 60°.
    Sin A = equals P over H equals fraction numerator A D over denominator A B end fraction
    Sin 60° = 25 over x
    fraction numerator square root of 3 over denominator 2 end fraction equals 25 over x
    straight x equals fraction numerator 50 over denominator square root of 3 end fraction equals 50 over 3 square root of 3 cm
    Since all sides are equal BC = 50 over 3 square root of 3
    We know that Area of triangle = 1 half cross times b cross times straight h
    equals 1 half cross times 50 over 3 square root of 3 cross times 25
    = 208.33square root of 3
    = 360.84 cm2                       ( ∴ square root of 3 = 1.73 )
    NOTE – We can use Pythagoras theorem too. Since perpendicular of an equilateral triangle bisects the side, implies that BD = x over 2 . So, in triangle ABD
    AB2 = AD2 + BD2
    Find x and then use Area of triangle = 1 half cross times b cross times straight h

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