Question
Consider A(0,1) and B(2,0) and P be a point on the line 4x+3y+9=0, co-ordinates of P such is maximum is
Hint:
The point p should satisfy the line AP and BP then find the lines passing through AP and BP gives point of intersection which is nothing but P.
The correct answer is:
Given That:
Consider A(0,1) and B(2,0) and P be a point on the line 4x+3y+9=0, co-ordinates of P such is maximum is
>>> Given:∣PA−PB∣ is maximum.
>>> A line passes through P having the equation 4x+3y+9=0
>>> Maximum value of ∣PA−PB∣=∣AB∣
>>> Equation of the line AB=y−0=2−00−1(x−0)
⇒2y=−x or x+2y=0
>>> The intersection of the lines x=−2y and 4x+3y+9=0 is
4×−2y+3y+9=0
⇒−8y+3y=−9
⇒−5y=−9
⇒y=
∴x=−2y=−2×=
>>> Hence the point is (, ).
Hence the point is (, ).
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