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General
Easy

Question

Consider an infinite geometric series with first term a and common ratio r. If its sum is 4 and the second term is 3/4, then

  1. a equals fraction numerator 4 over denominator 7 end fraction comma blank r equals fraction numerator 3 over denominator 7 end fraction   
  2. a equals 2 comma blank r equals fraction numerator 3 over denominator 8 end fraction  
  3. a equals fraction numerator 3 over denominator 2 end fraction comma r equals fraction numerator 1 over denominator 2 end fraction   
  4. a equals 3 comma blank r equals fraction numerator 1 over denominator 4 end fraction  

The correct answer is: a equals 3 comma blank r equals fraction numerator 1 over denominator 4 end fraction


    Sum is 4 and second term is ¾. It is given that first term is a and common ratio is r. Hence,
    fraction numerator a over denominator 1 minus r end fraction equals 4 and a r equals 3 divided by 4 blank rightwards double arrow r equals fraction numerator 3 over denominator 4 a end fraction
    Therefore,
    fraction numerator a over denominator 1 minus fraction numerator 3 over denominator 4 a end fraction end fraction equals 4 blank rightwards double arrow fraction numerator 4 a to the power of 2 end exponent over denominator 4 a minus 3 end fraction equals 4
    rightwards double arrow a to the power of 2 end exponent minus 4 a plus 3 equals 0
    rightwards double arrow open parentheses a minus 1 close parentheses open parentheses a minus 3 close parentheses equals 0
    rightwards double arrow a equals 1 or 3
    When a equals 1 comma blank r equals 3 divided by 4 and when a equals 3 comma blank r equals 1 divided by 4

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