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For x blank R blank element of comma blank x blank not equal to blank minus 1 comma ifleft parenthesis 1 plus x right parenthesis to the power of 2016 end exponent plus x left parenthesis 1 plus x right parenthesis to the power of 2015 end exponent plus x to the power of 2 end exponent left parenthesis 1 plus x right parenthesis to the power of 2014 end exponent plus midline horizontal ellipsis plus x to the power of 2016 end exponent equals stretchy sum from i equals 0 to 2016 of   a subscript i end subscript x to the power of i end exponent then a subscript 17 end subscript blankis equal to

  1. fraction numerator 2017 factorial over denominator 17 factorial 2000 factorial end fraction    
  2. fraction numerator 2016 factorial over denominator 17 factorial 1999 factorial end fraction    
  3. fraction numerator 2016 factorial over denominator 16 factorial end fraction    
  4. fraction numerator 2017 factorial over denominator 2000 factorial end fraction    

The correct answer is: fraction numerator 2017 factorial over denominator 17 factorial 2000 factorial end fraction


    We have
    table row cell left parenthesis 1 plus x right parenthesis to the power of 2016 end exponent fraction numerator open parentheses fraction numerator x over denominator 1 plus x end fraction close parentheses to the power of 2017 end exponent minus 1 over denominator fraction numerator 1 over denominator 1 plus x end fraction minus 1 end fraction equals stretchy sum from i equals 0 to 2016 of   a subscript i end subscript x to the power of i end exponent end cell row cell left parenthesis 1 plus x right parenthesis to the power of 2017 end exponent fraction numerator left parenthesis 1 plus x right parenthesis to the power of 2017 end exponent minus x to the power of 2017 end exponent over denominator left parenthesis 1 plus x right parenthesis to the power of 2017 end exponent end fraction equals stretchy sum from i equals 0 to 2016 of   a subscript i end subscript x to the power of i end exponent end cell end table
    left parenthesis 1 plus x right parenthesis to the power of 2017 end exponent minus x to the power of 2017 end exponent equals stretchy sum from i equals 0 to 2016 of   a subscript i end subscript x to the power of i end exponent
    Therefore,
    a subscript 17 end subscript equals text  Coefficient of  end text x to the power of 17 end exponent text  in  end text left parenthesis x plus 1 right parenthesis to the power of 2017 end exponent equals blank to the power of 2017 end exponent C subscript 17 end subscript equals fraction numerator 2017 factorial over denominator 17 factorial 2000 factorial end fraction

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