Given such that χ=0 is the only real root of if , then in the interval [−1, 1]

The correct answer is: P(-1) is not minimum but is the maximum of

As is a solution for , we have Therefore,
Further, we have , which implies that,

As , only when and is differentiable in , we shall have the maximum and minimum at the points and 1 only AIso, we have, Therefore,
Maximum value of Maximum value of
Minimum value of Minimum value of
l1n the interval , we have,

As has only one root, that is, has no real roots Therefore, (30) Thus, Therefore, we have and That is,

Hence, is increasing in Therefore, maximum value of
Similarly, is decreasing in −1, Therefore, minimum value of does not occur at
Hence, the correct answer is option (B).