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If open parentheses 4 close parentheses to the power of log subscript 9 end subscript invisible function application 3 end exponent plus open parentheses 9 close parentheses to the power of log subscript 2 end subscript invisible function application 4 end exponent equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent comma then x is equal to

  1. 2  
  2. 3  
  3. 10  
  4. 30  

The correct answer is: 10


    open parentheses 4 close parentheses to the power of log subscript 9 end subscript invisible function application 3 end exponent plus open parentheses 9 close parentheses to the power of log subscript 2 end subscript invisible function application 4 end exponent equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent
    rightwards double arrow open parentheses 4 close parentheses to the power of fraction numerator 1 over denominator 2 end fraction log subscript 3 end subscript invisible function application 3 end exponent plus open parentheses 9 close parentheses to the power of 2 end exponent log subscript 2 end subscript invisible function application 2 equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent rightwards double arrow 2 plus 81 equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent rightwards double arrow 83 equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent
    rightwards double arrow x
    equals 10

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