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Maths-

General

Easy

Question

If $A equals open square brackets table row 1 0 1 row 0 1 1 row 1 0 0 end table close square brackets$ , then A is

Symmetric
Skew-symmetric
Non-singular
Singular

The correct answer is: Non-singular

$capital delta equals open square brackets table row 1 0 1 row 0 1 1 row 1 0 0 end table close square brackets equals negative 1 not equal to 0$ , hence matrix is non-singular.

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