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Question

If $A equals left curly bracket x blank colon x$ is a multiple of $blank 4 right curly bracket$ and,
$B equals left curly bracket x blank colon x blank$ is a multiple of $blank 6 right curly bracket$ , then $A intersection B$ consists of multiples of

(a) 16
12
8
4

The correct answer is: 12

Let $x element of A intersection B.$ Then,
$x element of A$ and $x element of B$
$rightwards double arrow x$ is a multiple of 4 and $x$ is a multiple of 6
$rightwards double arrow x$ is a multiple of 4 and 6 both
$rightwards double arrow x$ is a multiple of 12

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