Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If $cos invisible function application open parentheses x minus y close parentheses equals negative 1$ , then $cos invisible function application x plus cos invisible function application y equals$

0
1
2
-1

The correct answer is: 0

Related Questions to study

$sec invisible function application A plus tan invisible function application A equals 3 rightwards double arrow sec invisible function application A equals$

$sec invisible function application A plus tan invisible function application A equals 3 rightwards double arrow sec invisible function application A equals$

The number of values of a for which $open parentheses a to the power of 2 end exponent minus 3 a plus 2 close parentheses x to the power of 2 end exponent plus open parentheses a to the power of 2 end exponent minus 5 a plus 6 close parentheses x plus a to the power of 2 end exponent minus 4 equals 0$ is an identity in x is

The number of values of a for which $open parentheses a to the power of 2 end exponent minus 3 a plus 2 close parentheses x to the power of 2 end exponent plus open parentheses a to the power of 2 end exponent minus 5 a plus 6 close parentheses x plus a to the power of 2 end exponent minus 4 equals 0$ is an identity in x is

If $alpha beta gamma$ are the roots of $x to the power of 3 end exponent minus x to the power of 2 end exponent minus 1 equals 0$ then the value of $sum fraction numerator 1 plus alpha over denominator 1 minus alpha end fraction$ is equal to

If $alpha beta gamma$ are the roots of $x to the power of 3 end exponent minus x to the power of 2 end exponent minus 1 equals 0$ then the value of $sum fraction numerator 1 plus alpha over denominator 1 minus alpha end fraction$ is equal to

parallel

Let $a x to the power of 2 end exponent plus b x plus c equals 0 comma a comma b comma c element of R comma$ be a quadratic equation. If $vertical line b vertical line greater than vertical line a plus c vertical line$ then the roots of the equation will be such that

Let $a x to the power of 2 end exponent plus b x plus c equals 0 comma a comma b comma c element of R comma$ be a quadratic equation. If $vertical line b vertical line greater than vertical line a plus c vertical line$ then the roots of the equation will be such that

If, for $f open parentheses x close parentheses equals x to the power of 2 end exponent plus 2 b x plus 2 c to the power of 2 end exponent text and end text g open parentheses x close parentheses equals negative x to the power of 2 end exponent minus 2 c x plus b to the power of 2 end exponent comma m i n f open parentheses x close parentheses greater than m a x g open parentheses x close parentheses comma$ then

If, for $f open parentheses x close parentheses equals x to the power of 2 end exponent plus 2 b x plus 2 c to the power of 2 end exponent text and end text g open parentheses x close parentheses equals negative x to the power of 2 end exponent minus 2 c x plus b to the power of 2 end exponent comma m i n f open parentheses x close parentheses greater than m a x g open parentheses x close parentheses comma$ then

Suppose A,B,C are defined as $A equals a to the power of 2 end exponent b plus a b to the power of 2 end exponent minus a to the power of 2 end exponent c minus a c to the power of 2 end exponent comma B equals b to the power of 2 end exponent c plus b c to the power of 2 end exponent minus a to the power of 2 end exponent b minus a b to the power of 2 end exponent comma$ and $C equals a to the power of 2 end exponent c plus c to the power of 2 end exponent a minus c b to the power of 2 end exponent minus c to the power of 2 end exponent b text where end text a greater than b greater than c greater than 0$ and the equation $A x to the power of 2 end exponent plus B x plus C equals 0$ has equal roots, then a,b,c are in

Suppose A,B,C are defined as $A equals a to the power of 2 end exponent b plus a b to the power of 2 end exponent minus a to the power of 2 end exponent c minus a c to the power of 2 end exponent comma B equals b to the power of 2 end exponent c plus b c to the power of 2 end exponent minus a to the power of 2 end exponent b minus a b to the power of 2 end exponent comma$ and $C equals a to the power of 2 end exponent c plus c to the power of 2 end exponent a minus c b to the power of 2 end exponent minus c to the power of 2 end exponent b text where end text a greater than b greater than c greater than 0$ and the equation $A x to the power of 2 end exponent plus B x plus C equals 0$ has equal roots, then a,b,c are in

parallel

Consider the quadratic equation $a x to the power of 2 end exponent minus b x plus c equals 0 comma a comma b comma c element of N$ If the given equation has two distinct real roots belonging to (1, 2)then

Consider the quadratic equation $a x to the power of 2 end exponent minus b x plus c equals 0 comma a comma b comma c element of N$ If the given equation has two distinct real roots belonging to (1, 2)then

If the sum of the roots of the quadratic equation, $a x to the power of 2 end exponent plus b x plus c equals 0$ is equal to sum of the squares of their reciprocals, then $fraction numerator a over denominator c end fraction comma fraction numerator b over denominator a end fraction comma fraction numerator c over denominator b end fraction$ are in :

If the sum of the roots of the quadratic equation, $a x to the power of 2 end exponent plus b x plus c equals 0$ is equal to sum of the squares of their reciprocals, then $fraction numerator a over denominator c end fraction comma fraction numerator b over denominator a end fraction comma fraction numerator c over denominator b end fraction$ are in :

All possible quadratic equations $a x to the power of 2 end exponent plus b x plus 1 equals 0$ taking $a stack I with hat on top left curly bracket 1 , 2 comma 3 comma horizontal ellipsis n right curly bracket comma b stack I with hat on top left curly bracket 1 comma negative 2 comma negative 3 comma horizontal ellipsis horizontal ellipsis minus n right curly bracket$ and if $open parentheses a subscript i end subscript comma b subscript i end subscript close parentheses i equals 1 , 2 comma 3 comma horizontal ellipsis.. n$ represent solution sets of these equations then $text å end text fraction numerator 1 over denominator a subscript i end subscript end fraction plus a to the power of ring operator end exponent fraction numerator 1 over denominator b subscript i end subscript end fraction$ equals

All possible quadratic equations $a x to the power of 2 end exponent plus b x plus 1 equals 0$ taking $a stack I with hat on top left curly bracket 1 , 2 comma 3 comma horizontal ellipsis n right curly bracket comma b stack I with hat on top left curly bracket 1 comma negative 2 comma negative 3 comma horizontal ellipsis horizontal ellipsis minus n right curly bracket$ and if $open parentheses a subscript i end subscript comma b subscript i end subscript close parentheses i equals 1 , 2 comma 3 comma horizontal ellipsis.. n$ represent solution sets of these equations then $text å end text fraction numerator 1 over denominator a subscript i end subscript end fraction plus a to the power of ring operator end exponent fraction numerator 1 over denominator b subscript i end subscript end fraction$ equals

parallel

Let $f left parenthesis x right parenthesis equals fraction numerator open parentheses 2 x to the power of 3 end exponent minus 9 x to the power of 2 end exponent plus 12 x plus 3 close parentheses left parenthesis x minus a right parenthesis over denominator left parenthesis x minus a right parenthesis end fraction$ If range of f(x) is a proper subset of the set of real numbers, then the most exhaustive set in which a lies is

Let $f left parenthesis x right parenthesis equals fraction numerator open parentheses 2 x to the power of 3 end exponent minus 9 x to the power of 2 end exponent plus 12 x plus 3 close parentheses left parenthesis x minus a right parenthesis over denominator left parenthesis x minus a right parenthesis end fraction$ If range of f(x) is a proper subset of the set of real numbers, then the most exhaustive set in which a lies is

If $open parentheses b to the power of 2 end exponent minus 4 a c close parentheses to the power of 2 end exponent open parentheses 1 plus 4 a to the power of 2 end exponent close parentheses less than 64 a to the power of 2 end exponent comma a less than 0 comma$ then maximum value of quadratic expression $a x to the power of 2 end exponent plus b x plus c$ is always less than

If $open parentheses b to the power of 2 end exponent minus 4 a c close parentheses to the power of 2 end exponent open parentheses 1 plus 4 a to the power of 2 end exponent close parentheses less than 64 a to the power of 2 end exponent comma a less than 0 comma$ then maximum value of quadratic expression $a x to the power of 2 end exponent plus b x plus c$ is always less than

Analyze the following graph of $f to the power of ´ end exponent left parenthesis x right parenthesis$ the which is incorrect about $f left parenthesis x right parenthesis text for end text alpha less than x less than beta$

Analyze the following graph of $f to the power of ´ end exponent left parenthesis x right parenthesis$ the which is incorrect about $f left parenthesis x right parenthesis text for end text alpha less than x less than beta$

parallel

If one root is square of other root of equation $x to the power of 2 end exponent plus p x plus q equals 0 comma q element of R$ then condition on

If one root is square of other root of equation $x to the power of 2 end exponent plus p x plus q equals 0 comma q element of R$ then condition on

Statement -1 : There exists only one real value of ‘k’ for which the real roots of the equation $k x to the power of 3 end exponent plus 3 x to the power of 2 end exponent minus 3 x plus 1 equals 0$ are in H.P. because
Statement - 2 : For a cubical equation $a x to the power of 3 end exponent plus b x to the power of 2 end exponent plus c x plus d equals 0 comma$ if b, c and d are non zero real and constant, then we can have only one real value of ‘a’ for which all real roots of $a x to the power of 3 end exponent plus b x to the power of 2 end exponent plus c x plus d equals 0$ are in H.P.

Statement -1 : There exists only one real value of ‘k’ for which the real roots of the equation $k x to the power of 3 end exponent plus 3 x to the power of 2 end exponent minus 3 x plus 1 equals 0$ are in H.P. because
Statement - 2 : For a cubical equation $a x to the power of 3 end exponent plus b x to the power of 2 end exponent plus c x plus d equals 0 comma$ if b, c and d are non zero real and constant, then we can have only one real value of ‘a’ for which all real roots of $a x to the power of 3 end exponent plus b x to the power of 2 end exponent plus c x plus d equals 0$ are in H.P.

Consider a triangle ABC. BE and CF are the medians drawn through the angular points B and C respectively and G is the centroid of the $capital delta$ ABC.
Statement – 1: If the points, A, E, G, F are concyclic then $angle A$ must be acute. because
Statement – 2: The medians of a triangle divide triangle into area wise two equal parts.

Consider a triangle ABC. BE and CF are the medians drawn through the angular points B and C respectively and G is the centroid of the $capital delta$ ABC.
Statement – 1: If the points, A, E, G, F are concyclic then $angle A$ must be acute. because
Statement – 2: The medians of a triangle divide triangle into area wise two equal parts.

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.