Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

$I f blank stack lim with x rightwards arrow infinity below invisible function application open parentheses fraction numerator x plus h over denominator x minus h end fraction close parentheses to the power of x end exponent equals 4 comma blank t h e n blank h equals$

${l o g}_{e} 2$
${l o g}_{10} 2$
${l o g}_{2} 2$
${l o g}_{2} 10$

The correct answer is: $l o g subscript e end subscript 2$

Related Questions to study

Arrange the following limits in descending order
i) $stack lim with x rightwards arrow 3 to the power of minus end exponent below invisible function application fraction numerator 3 minus x over denominator open vertical bar x minus 3 close vertical bar end fraction$
ii) $stack lim with x rightwards arrow 0 below invisible function application fraction numerator left parenthesis 1 plus x right parenthesis to the power of 1 divided by 8 end exponent minus left parenthesis 1 minus x right parenthesis to the power of 1 divided by 8 end exponent over denominator x end fraction$
iii) $stack lim with x rightwards arrow 0 below invisible function application fraction numerator t a n x minus s i n x over denominator x to the power of 3 end exponent end fraction$
iv) $stack lim with x rightwards arrow infinity below invisible function application open curly brackets square root of x to the power of 2 end exponent plus 6 x plus 7 end root minus x close curly brackets$

Arrange the following limits in descending order
i) $stack lim with x rightwards arrow 3 to the power of minus end exponent below invisible function application fraction numerator 3 minus x over denominator open vertical bar x minus 3 close vertical bar end fraction$
ii) $stack lim with x rightwards arrow 0 below invisible function application fraction numerator left parenthesis 1 plus x right parenthesis to the power of 1 divided by 8 end exponent minus left parenthesis 1 minus x right parenthesis to the power of 1 divided by 8 end exponent over denominator x end fraction$
iii) $stack lim with x rightwards arrow 0 below invisible function application fraction numerator t a n x minus s i n x over denominator x to the power of 3 end exponent end fraction$
iv) $stack lim with x rightwards arrow infinity below invisible function application open curly brackets square root of x to the power of 2 end exponent plus 6 x plus 7 end root minus x close curly brackets$

$I f blank open square brackets x close square brackets d e n o t e s blank t h e blank g r e a t e s t blank i n t e g e r blank l e s s blank t h a n blank o r blank e q u a l blank t o blank x blank t h e n blank$ $stack lim with n rightwards arrow infinity below invisible function application fraction numerator 1 over denominator n to the power of 4 end exponent end fraction open curly brackets open square brackets 1 to the power of 3 end exponent x close square brackets plus open square brackets 2 to the power of 3 end exponent x close square brackets plus open square brackets 3 to the power of 3 end exponent x close square brackets plus horizontal ellipsis plus left square bracket n to the power of 3 end exponent x right square bracket close curly brackets equals$

$I f blank open square brackets x close square brackets d e n o t e s blank t h e blank g r e a t e s t blank i n t e g e r blank l e s s blank t h a n blank o r blank e q u a l blank t o blank x blank t h e n blank$ $stack lim with n rightwards arrow infinity below invisible function application fraction numerator 1 over denominator n to the power of 4 end exponent end fraction open curly brackets open square brackets 1 to the power of 3 end exponent x close square brackets plus open square brackets 2 to the power of 3 end exponent x close square brackets plus open square brackets 3 to the power of 3 end exponent x close square brackets plus horizontal ellipsis plus left square bracket n to the power of 3 end exponent x right square bracket close curly brackets equals$

$stack lim with x rightwards arrow 0 below invisible function application open parentheses c o s e c x minus fraction numerator 1 over denominator x end fraction close parentheses equals$

$stack lim with x rightwards arrow 0 below invisible function application open parentheses c o s e c x minus fraction numerator 1 over denominator x end fraction close parentheses equals$

parallel

If f (x) = $fraction numerator x over denominator sin invisible function application x end fraction text and g end text left parenthesis x right parenthesis text = end text fraction numerator x over denominator tan invisible function application x end fraction$ where 0 < x ≤ 1 then in the interval

If f (x) = $fraction numerator x over denominator sin invisible function application x end fraction text and g end text left parenthesis x right parenthesis text = end text fraction numerator x over denominator tan invisible function application x end fraction$ where 0 < x ≤ 1 then in the interval

The function 2|x – 2| + |x – 3| is an increasing function when x belongs to the interval

The function 2|x – 2| + |x – 3| is an increasing function when x belongs to the interval

The function 2x³ – 9x² + 12x – 3 is increasing when x belongs to the interval

The function 2x³ – 9x² + 12x – 3 is increasing when x belongs to the interval

parallel

There is an error of 0.05cm in measuring the circumference 20cm of a circle. Then the percentage error in the area is

There is an error of 0.05cm in measuring the circumference 20cm of a circle. Then the percentage error in the area is

In the curve y = a log(x² – a²) the sum of the lengths and the sub tangent at any point varies as

In the curve y = a log(x² – a²) the sum of the lengths and the sub tangent at any point varies as

If the tangent at any point of the curve $square root of x plus square root of y equals square root of a$ meets the co-ordinate axes at A and B then OA + OB =

If the tangent at any point of the curve $square root of x plus square root of y equals square root of a$ meets the co-ordinate axes at A and B then OA + OB =

parallel

The plane 2x -2y + z + 12 = 0 touches the sphere x² + y² + z² – 2x – 4y + 2z – 3 = 0 at the point

The plane 2x -2y + z + 12 = 0 touches the sphere x² + y² + z² – 2x – 4y + 2z – 3 = 0 at the point

$stack lim with x rightwards arrow 0 below invisible function application fraction numerator open parentheses a b close parentheses to the power of x end exponent minus a to the power of x end exponent minus b to the power of x end exponent plus 1 over denominator x to the power of 2 end exponent end fraction equals$

$stack lim with x rightwards arrow 0 below invisible function application fraction numerator open parentheses a b close parentheses to the power of x end exponent minus a to the power of x end exponent minus b to the power of x end exponent plus 1 over denominator x to the power of 2 end exponent end fraction equals$

$stack lim with x rightwards arrow infinity below invisible function application fraction numerator x over denominator square root of 4 x to the power of 2 end exponent plus 1 minus 1 end root end fraction equals$

$stack lim with x rightwards arrow infinity below invisible function application fraction numerator x over denominator square root of 4 x to the power of 2 end exponent plus 1 minus 1 end root end fraction equals$

parallel

The IUPAC name 'of is:

The IUPAC name 'of is:

Chemistry-General

The IUPAC name of the compound
is:

The IUPAC name of the compound
is:

Chemistry-General

The correct name of
is:

The correct name of
is:

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.