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Question

If n open parentheses A subscript i end subscript close parentheses equals i plus 1 and A subscript 1 end subscript subset of A subscript 2 end subscript subset of A subscript 3 end subscript subset of horizontal ellipsis subset of A subscript 99 end subscript comma then n open parentheses not stretchy ⋃ from i equals 1 to 99 of A subscript i end subscript close parentheses equals

  1. (a) 99  
  2. 98  
  3. 100  
  4. 101  

The correct answer is: 100


    It is given that
    A subscript 1 end subscript subset of A subscript 2 end subscript subset of A subscript 3 end subscript horizontal ellipsis subset of A subscript 99 end subscript
    not stretchy ⋃ from i equals 1 to 999 of A subscript i end subscript equals A subscript 99 end subscript
    rightwards double arrow n open parentheses not stretchy ⋃ from i equals 1 to 99 of A subscript i end subscript close parentheses equals n open parentheses A subscript 99 end subscript close parentheses equals 99 plus 1 equals 100

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