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If $n open parentheses A subscript i end subscript close parentheses equals i plus 1$ and $A subscript 1 end subscript subset of A subscript 2 end subscript subset of A subscript 3 end subscript subset of horizontal ellipsis subset of A subscript 99 end subscript comma$ then $n open parentheses not stretchy ⋃ from i equals 1 to 99 of A subscript i end subscript close parentheses equals$

(a) 99
98
100
101

The correct answer is: 100

It is given that
$A subscript 1 end subscript subset of A subscript 2 end subscript subset of A subscript 3 end subscript horizontal ellipsis subset of A subscript 99 end subscript$
$not stretchy ⋃ from i equals 1 to 999 of A subscript i end subscript equals A subscript 99 end subscript$
$rightwards double arrow n open parentheses not stretchy ⋃ from i equals 1 to 99 of A subscript i end subscript close parentheses equals n open parentheses A subscript 99 end subscript close parentheses equals 99 plus 1 equals 100$

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