Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If $n open parentheses A cross times B close parentheses equals 45 comma$ then $n left parenthesis A right parenthesis$ cannot be

15
17
5
9

The correct answer is: 17

We have,
$n open parentheses A cross times B close parentheses equals 45$
$rightwards double arrow n open parentheses A close parentheses cross times n open parentheses B close parentheses equals 45$
$rightwards double arrow n left parenthesis A right parenthesis$ and $n open parentheses B close parentheses$ are factors of 45 such that their product is 45
Hence, $n left parenthesis A right parenthesis$ cannot be 17

Related Questions to study

An investigator interviewed 100 students to determine the performance of three drinks milk, coffee and tea. The investigator reported that 10 students take all three drinks milk, coffee and tea; 20 students take milk and coffee, 30 students take coffee and tea, 25 students take mile and tea, 12 students take milk only, 5 students take coffee only and 8 students take tea only. Then, the number of students who did not take any of the three drinks, is

An investigator interviewed 100 students to determine the performance of three drinks milk, coffee and tea. The investigator reported that 10 students take all three drinks milk, coffee and tea; 20 students take milk and coffee, 30 students take coffee and tea, 25 students take mile and tea, 12 students take milk only, 5 students take coffee only and 8 students take tea only. Then, the number of students who did not take any of the three drinks, is

Let $L$ denote the set of all straight lines in a plane. Let a relation $R$ be defined by $alpha blank R blank beta left right double arrow alpha perpendicular beta comma alpha comma beta element of L.$ Then $R$ is

Let $L$ denote the set of all straight lines in a plane. Let a relation $R$ be defined by $alpha blank R blank beta left right double arrow alpha perpendicular beta comma alpha comma beta element of L.$ Then $R$ is

The relation ‘is not equal to’ is defined on $R comma$ is

The relation ‘is not equal to’ is defined on $R comma$ is

parallel

Let $Z$ denote the set of integers, then
$open curly brackets x element of Z colon open vertical bar x minus 3 close vertical bar less than 4 close curly brackets n open curly brackets x element of Z colon open vertical bar x minus 4 close vertical bar less than 5 close curly brackets equals$

Let $Z$ denote the set of integers, then
$open curly brackets x element of Z colon open vertical bar x minus 3 close vertical bar less than 4 close curly brackets n open curly brackets x element of Z colon open vertical bar x minus 4 close vertical bar less than 5 close curly brackets equals$

If $A$ and $B$ are two given sets, then $A intersection open parentheses A intersection B close parentheses to the power of c end exponent$ is equal to

If $A$ and $B$ are two given sets, then $A intersection open parentheses A intersection B close parentheses to the power of c end exponent$ is equal to

For any two sets $A$ and $B$ , $A minus left parenthesis A minus B right parenthesis$ equals

For any two sets $A$ and $B$ , $A minus left parenthesis A minus B right parenthesis$ equals

parallel

If $a comma blank b comma blank c comma d$ are in G.P., then $open parentheses b minus c close parentheses to the power of 2 end exponent plus open parentheses c minus a close parentheses to the power of 2 end exponent plus open parentheses d minus b close parentheses to the power of 2 end exponent$ in equal to

If $a comma blank b comma blank c comma d$ are in G.P., then $open parentheses b minus c close parentheses to the power of 2 end exponent plus open parentheses c minus a close parentheses to the power of 2 end exponent plus open parentheses d minus b close parentheses to the power of 2 end exponent$ in equal to

The third term of a geometric progression is 4. The product of the first five terms is

The third term of a geometric progression is 4. The product of the first five terms is

Concentric circles of radii 1, 2, 3,…,100 cm are drawn. The interior of the smallest circle is coloured red and the angular regions are coloured alternately green and red, so that no two adjacent regions are of the same colour. Then, the total area of the green regions in sq. cm is equal to

Concentric circles of radii 1, 2, 3,…,100 cm are drawn. The interior of the smallest circle is coloured red and the angular regions are coloured alternately green and red, so that no two adjacent regions are of the same colour. Then, the total area of the green regions in sq. cm is equal to

parallel

The geometric mean between $negative 9$ and $negative 16$ is

The geometric mean between $negative 9$ and $negative 16$ is

If the sides of a right angled triangle are in A.P., then the sines of the acute angles are

If the sides of a right angled triangle are in A.P., then the sines of the acute angles are

If $a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma horizontal ellipsis comma a subscript 2 n plus 1 end subscript$ are in A.P., then $fraction numerator a subscript 2 n plus 1 end subscript minus a subscript 1 end subscript over denominator a subscript 2 n plus 1 end subscript plus a subscript 1 end subscript end fraction plus fraction numerator a subscript 2 n end subscript minus a subscript 2 end subscript over denominator a subscript 2 n end subscript plus a subscript 2 end subscript end fraction plus horizontal ellipsis plus fraction numerator a subscript n plus 2 end subscript minus a subscript n end subscript over denominator a subscript n plus 2 end subscript plus a subscript n end subscript end fraction$ is equal to

If $a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma horizontal ellipsis comma a subscript 2 n plus 1 end subscript$ are in A.P., then $fraction numerator a subscript 2 n plus 1 end subscript minus a subscript 1 end subscript over denominator a subscript 2 n plus 1 end subscript plus a subscript 1 end subscript end fraction plus fraction numerator a subscript 2 n end subscript minus a subscript 2 end subscript over denominator a subscript 2 n end subscript plus a subscript 2 end subscript end fraction plus horizontal ellipsis plus fraction numerator a subscript n plus 2 end subscript minus a subscript n end subscript over denominator a subscript n plus 2 end subscript plus a subscript n end subscript end fraction$ is equal to

parallel

If $S subscript n end subscript$ denotes the sum of first $n$ terms of an A.P. whose first term is $a$ and $fraction numerator S subscript n x end subscript over denominator S subscript x end subscript end fraction$ is independent of $x$ , then $S subscript p end subscript equals$

If $S subscript n end subscript$ denotes the sum of first $n$ terms of an A.P. whose first term is $a$ and $fraction numerator S subscript n x end subscript over denominator S subscript x end subscript end fraction$ is independent of $x$ , then $S subscript p end subscript equals$

If the sum of $n$ terms of an A.P. is $c n left parenthesis n minus 1 right parenthesis$ , where $c not equal to 0$ , then sum of the squares of these terms is

If the sum of $n$ terms of an A.P. is $c n left parenthesis n minus 1 right parenthesis$ , where $c not equal to 0$ , then sum of the squares of these terms is

Find the sum $open parentheses x plus 2 close parentheses to the power of n minus 1 end exponent plus open parentheses x plus 2 close parentheses to the power of n minus 2 end exponent open parentheses x plus 1 close parentheses plus open parentheses x plus 2 close parentheses to the power of n minus 3 end exponent open parentheses x plus 1 close parentheses to the power of 2 end exponent plus horizontal ellipsis plus open parentheses x plus 1 close parentheses to the power of n minus 1 end exponent$

Find the sum $open parentheses x plus 2 close parentheses to the power of n minus 1 end exponent plus open parentheses x plus 2 close parentheses to the power of n minus 2 end exponent open parentheses x plus 1 close parentheses plus open parentheses x plus 2 close parentheses to the power of n minus 3 end exponent open parentheses x plus 1 close parentheses to the power of 2 end exponent plus horizontal ellipsis plus open parentheses x plus 1 close parentheses to the power of n minus 1 end exponent$

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.