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Question

If $R$ be a relation $less than$ from $A equals left curly bracket 12 comma 34 right curly bracket$ to $B equals open curly brackets 13 comma 5 close curly brackets blank i. e. blank open parentheses a comma b close parentheses element of R left right double arrow a less than b comma$ then $R blank o blank R to the power of negative 1 end exponent$ is

$\{(1,3), (1,5), (2,3), (2,5), (3,5), (4,5)\}$
${(3,1), (5,1), (3,2), (5,2), (5,3), (5,4)}$
${(3,3), (3,5), (5,3), (5,5)}$
${(3,3), (3,4), (4,5)}$

The correct answer is: $left curly bracket open parentheses 33 close parentheses comma open parentheses 35 close parentheses comma open parentheses 53 close parentheses comma left parenthesis 55 right parenthesis right curly bracket$

We have,
$R equals left curly bracket open parentheses 13 close parentheses comma open parentheses 15 close parentheses comma open parentheses 23 close parentheses comma open parentheses 25 close parentheses comma open parentheses 35 close parentheses comma left parenthesis 45 right parenthesis right curly bracket$
$rightwards double arrow R to the power of negative 1 end exponent equals left curly bracket open parentheses 31 close parentheses comma open parentheses 51 close parentheses comma open parentheses 32 close parentheses comma open parentheses 52 close parentheses comma open parentheses 53 close parentheses comma left parenthesis 54 right parenthesis right curly bracket$
Hence, $R blank o blank R to the power of negative 1 end exponent equals left curly bracket open parentheses 33 close parentheses comma open parentheses 35 close parentheses comma open parentheses 53 close parentheses comma left parenthesis 55 right parenthesis right curly bracket$

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