Maths-
General
Easy

Question

If t a n invisible function application A plus t a n invisible function application B equals p and c o t invisible function application A plus c o t invisible function application B equals q then c o t invisible function application left parenthesis A plus B right parenthesis equals

  1. fraction numerator p minus q over denominator p q end fraction    
  2. fraction numerator q minus p over denominator p q end fraction    
  3. fraction numerator p q over denominator p plus q end fraction    
  4. fraction numerator p q over denominator p minus q end fraction    

The correct answer is: fraction numerator q minus p over denominator p q end fraction


    t a n invisible function application left parenthesis theta plus alpha right parenthesis equals 1 rightwards double arrow fraction numerator t a n invisible function application theta plus t a n invisible function application alpha over denominator 1 minus t a n invisible function application theta t a n invisible function application alpha end fraction equals 1
    rightwards double arrow t a n invisible function application alpha equals fraction numerator 1 minus t a n invisible function application theta over denominator 1 plus t a n invisible function application theta end fraction

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